如何在CakePHP中定义脚本？

Question

Whenever I am trying to define 2 scripts this way:

echo $this->Html->script(array('jquery', 'prototype'));

only prototype is working.

When I do it this way:

echo $this->Html->script(array('prototype', 'jquery'));

only jquery is working.

How do I fix it so both are working?

Answer 1

That is because they both use the $ variable, and the second script overwrites the first.

Try creating a script for the middle that only contains:

$j = $.noConflict(); //sets `$j` as the jQuery variable

Then do:

echo $this->Html->script(array('jquery', 'middleScript', 'prototype'));

Answer 2

在jQuery之后立即添加<script type="text/javascript">jQuery.noConflict();</script> ， 然后添加原型。