我用javascript生成了html代码（很多div）。 现在我想用GetElementById查找生成的div

Question

GetElementById works if I manually added a div id="something" inside the body and use window.onload = init method in the script to get it. Works great.

But if I used a for loop to generate divs where id's is 1,2,3 and so on. I can't get it. Is there a way to get to those generated divs?

This is what generates the html code (just to be clear what I mean):

for(i=0; i<randomizeColoursList.length; i++)
{
    document.getElementById("renderColors").innerHTML += 
        '<div class=\"box\"><div class=\"' + i + '\"><font color=\"' 
        + randomizeColoursList[i] + '\">' 
        + "" + '<img src=\"dist/card_bg.gif\"></div></div>';                    
}   

Generates one of these:

<div class="8"><font color="#3be6c4"><img src="dist/card_bg.gif"></font></div>

Div with class 8 is the id I want to get for example. But is says it's null.

Thanks.

Answer 1

The id is null because you haven't specified it in your markup creation. Looks like you're assigning the id value to class instead.

Answer 2

Generate something more like this:

<div id="div1" class="8"><font color="#3be6c4"><img src="dist/card_bg.gif"></font></div> 

Also, you don't need to use font tags, nor should you use them. Just add the styling to the div.

<div id="div1" class="8" style="color:#3be6c4;"><img src="dist/card_bg.gif"></div> 

Answer 3

The way you're going about this is a little backwards. If you write your code like I have below, then you don't need to give the divs IDs, you end up with an array full of references to them anyway.

var i, div, img;
var createdDivs = [];
for(i=0; i<randomizeColoursList.length; i++)
{
    div = document.createElement('div');
    img = document.createElement('img');
    div.className = "box";
    div.style.backgroundColor = randomizeColoursList[i];
    div.style.color = randomizeColoursList[i];
    img.src = "dist/card_bg.gif"

    div.appendChild(img);
    document.getElementById("renderColours").appendChild(div);                

    createdDivs.push(div);
}  

Live link: http://jsfiddle.net/7HjLL/