iOS / iPhone-单击另一个按钮时隐藏一个按钮

Question

I have a settings view in my app which has a couple of buttons (actually UISwitches). If the "off" setting on one of the switches is selected, I'd like to hide the second switch immediately. Can this be done?

Answer 1

IBOutlet UIButton *btn1;
IBOutlet UIButton *btn2;

write the above 2 lines in your .h file and set the outlets with XIB.

Now create a method called hideButton

-(IBAction)hideButton
{
       btn1.hidden = YES;
}

in XIB attach this method with btn2 . So now when you click on btn2 it will hide btn1 .

Answer 2

Connect the two switches as outlets. lets say switch1 & switch2.

Connect this function to the valueChanged action.

- (IBAction)mySwitch1:(id)sender { 
    [switch2 setHidden:!(switch1.isOn)];
}

Now when switch1 is not on then switch2 will be hidden.

Answer 3

Add a target to the first switch which on value change calls the instance of the second switch and hides it.

Add the target:

    [switch1 addTarget:self action:@selector(switchToggled:) forControlEvents: UIControlEventValueChanged];

Calls this method:

- (void) switchToggled:(UISwitch*)switch {
 if ([switch isOn]) switch2.hidden = YES;
 else switch2.hidden = NO;
}

NJones if statement is more effective though.

Answer 4

Swift 4

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Within your function do the following:

btn1.isHidden = true