用jQuery加载可变的php页面

Question

My goals is to load a div from any php page. I'm using the jQuery function .load for this:

    $(document).ready(function(){
        $('#crumb').load('example.php #hello');
    });
    </script>

I want example.php to be welcome.php or test.php or about.php. It depends on which page is loaded within the container of the index. Any ideas?

Answer 1

Try this:

function $_GET(q, s) { 
    s = s ? s : window.location.search; 
    var re = new RegExp('&'+q+'(?:=([^&]*))?(?=&|$)','i'); 
    return (s=s.replace(/^?/,'&').match(re)) ? (typeof s[1] == 'undefined' ? '' : decodeURIComponent(s[1])) : undefined; 
}

/*
 * Edited here
 */
$(document).ready(function(){
    $('#crumb').load(($_GET('p') !== undefined ? ('index.php?p=' + $_GET('p')) : 'welcom.php') + ' #hello');
});

Answer 2

To do so consider the following:

Javascript

function GetDiv(url,tdiv) {
$("#GetDivResult").load(url,function() {
HandleResult(tdiv);
});
}
function HandleResult(tdiv){
$("#crumb").html($(tdiv).html());
}
function StartNow(){
var url = prompt("Enter the URL");
var tdiv = prompt("What DIV you want to show? example: #hello");
GetDiv(url,tdiv);
}

HTML

<a href="#" onclick="StartNow()">Begin</a>
<div id="GetDivResult" style="display: none;"></div>
<div id="crumb"></div>

This is a simple example so you get the idea behind it..