在C中获取用户输入的最简单方法是什么？

Question

There seem to be a LOT of ways you can get user input in C.

What is the easiest way that requires little code?

Basically I need to display this:

Enter a file name: apple.text

Basically I need to ask the user for a file name. So I need something that just gets that one word that the user will be inputting.

Answer 1

The simplest "correct" way is probably this one, taken from Bjarne Stroustrup's paper Learning Standard C++ As A New Language .

(Note: I changed Bjarne's code to check for isspace() instead of just end of line. Also, due to @matejkramny's comment, to use while(1) instead of while(true) ...and so long as we're being heretical enough to edit Stroustrup's code, I've subbed in C89 comments instead of C++ style too. :-P)

#include <stdio.h>
#include <ctype.h>
#include <stdlib.h>

void quit() /* write error message and quit */
{
    fprintf(stderr, "memory exhausted\n");
    exit(1);
}

int main()
{
    int max = 20;
    char* name = (char*) malloc(max); /* allocate buffer */
    if (name == 0) quit();

    printf("Enter a file name: ");

    while (1) { /* skip leading whitespace */
        int c = getchar();
        if (c == EOF) break; /* end of file */
        if (!isspace(c)) {
             ungetc(c, stdin);
             break;
        }
    }

    int i = 0;
    while (1) {
        int c = getchar();
        if (isspace(c) || c == EOF) { /* at end, add terminating zero */
            name[i] = 0;
            break;
        }
        name[i] = c;
        if (i == max - 1) { /* buffer full */
            max += max;
            name = (char*) realloc(name, max); /* get a new and larger buffer */
            if (name == 0) quit();
        }
        i++;
    }

    printf("The filename is %s\n", name);
    free(filename); /* release memory */
    return 0;
}

That covers:

• skipping whitespace until you reach character input
• expanding the string buffer dynamically to fit arbitrary size strings
• handling conditions of when memory can't be allocated

Are there simpler but broken solutions, which might even run a bit faster? Absolutely!!

If you use scanf into a buffer with no limit on the read size, then your input exceeds the size of the buffer, it will create a security hole and/or crash.

Limiting the size of the reading to, say, only 100 unique characters of a filename might seem better than crashing. But it can be worse; for instance if the user meant (...)/dir/foo/bar.txt but you end up misinterpreting their input and overwriting a file called bar.t which perhaps they cared about.

It's best to get into good habits early in dealing with these issues. My opinion is that if your requirements justify something close-to-the-metal and "C-like", it's well worth it to consider the jump to C++. It was designed to manage precisely these concerns--with techniques that are robust and extensible, yet still perform well.

Answer 2

scanf seems to work in a non-hostile environment. In other words, you're making a simple utility program for yourself.

BUFSIZ usually far exceeds the size limits of UNIX pathnames.

#include <stdio.h>

int main(void) {
  char str[BUFSIZ];                                                                                                                                                                             

  printf("Enter a file name: ");                                                                                                                                                                
  scanf("%s", str);                                                                                                                                                                             

  printf("You entered: %s\n", str);                                                                                                                                                             
}

If you need to accumulate data in a program that could be the target of buffer overrun, you might need a bit more.

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

char * prompt_and_read(const char * prompt) {
  char * response;
  char * bufsize;

  printf("%s", prompt);
  asprintf(&bufsize, "%%%us", BUFSIZ);

  if((response = malloc(BUFSIZ + 1)) == NULL) {
    fprintf(stderr,"out of memory\n");
    exit(1);
  }
  scanf(bufsize, response);
  free(bufsize);
  return response;
}

int main ( void ) {
  char * pathname;

  pathname = prompt_and_read("Enter a file name: ");
  printf("You entered: [%s]\n", pathname);
  free(pathname);

  return 0;
}

Answer 3

#include <stdio.h>
int main(void)
{
    char file[100];
    printf("File Name?: \n");
    fgets(file, 100, stdin);
    printf("Your input: %s", file);
}

Answer 4

#include <iostream>
#include <string>

using namespace std;

int main()
{
    cout << "Enter a file name:";

    string filepath;
    cin >> filepath;
}

Answer 5

you should write your own fgets() wrapper function that reads a line of input into a buffer of a specified size and that removes the newline char that fgets() also reads. you could also return a status of whether or not the whole line was able to fit into the buffer (ie. is the newline at the end of the buffer). you shouldn't ever really use scanf or gets unless you want overflows.

EDIT: thought i might provide some basic code:

typedef unsigned char BOOL;
#define TRUE   1
#define FALSE  0

/* wraps fgets, returns FALSE if the whole line couldn't fit into the buffer */
BOOL read_input(char *dest, size_t len)
{
   /* our temp buffer needs to hold the extra new line char (len + 1)
        * should also add error checking to malloc */
   BOOL bSuccess = TRUE;
   size_t total_len = len + 1;
   char *temp = (char*) malloc( total_len * sizeof(char) );

   fgets(temp, total_len, stdin);

   /* if the whole line wasn't read, we'll return FALSE but still copy temp into dest */
   if (temp[strlen(temp) - 1] != '\n')
      bSuccess = FALSE;
   else
      temp[strlen(temp) - 1] = '\0'; /* overwrite the '\n' if it does infact exist */

   strcpy(dest, temp);

   free(temp);
   return bSuccess;
}

Answer 6

Use this simple code

#include"stdio.h"
#include"stdlib.h"
main()
{
    int i=0,j=0;
    char c,buf[100];

start:
    printf("Enter the name:");
    while ( (c=getchar()) != '\n' )
    {
            buf[i++]=c;
            buf[i]='\0';
    }
    if ( buf[0] == '\0')
    {
    printf("invalid name\n");
    goto start;
    }
    else
    printf("Your name is valid\nName = %s\n",buf);
      }