[英]How to sort ArrayList values by name in java
I am getting student information from database, 我正在从数据库中获取学生信息,
ArrayList<Student> studentList = session.createQuery("from Student order by Date").list();
the studentList contains name , id ,marks, by date. studentList包含按日期显示的名称,id,标记。 I want to display this arraylist by name, becase the same student name contains different date. 我想按名称显示此arraylist,因为同一名学生的姓名包含不同的日期。 How to sort this from arraylist. 如何从arraylist排序。 Ex studentList value is 以前的StudentList值为
1 x 2010-10-01
2 y 2010-10-05
3 z 2010-10-15
1 x 2010-10-10
1 x 2010-10-17
2 y 2010-10-15
4 xx 2010-10-10
I want to display this to 我想显示这个
1 x 2010-10-01
1 x 2010-10-10
1 x 2010-10-17
2 y 2010-10-05
2 y 2010-10-15
3 z 2010-10-15
4 xx 2010-10-10
and store this to another array list 并将其存储到另一个数组列表
There are plenty of questions to look at that answer this, such as: https://stackoverflow.com/questions/2784514/sort-arraylist-of-custom-objects-by-property 有很多问题需要解决,例如: https : //stackoverflow.com/questions/2784514/sort-arraylist-of-custom-objects-by-property
But here is an example program of what to do. 但是这里是一个示例程序。 I assumed you wanted to sort by name first, and then date. 我假设您想先按名称排序,然后按日期排序。 You can put logic to do that in the custom comparator. 您可以在自定义比较器中添加逻辑来做到这一点。
import java.util.*;
public class SortExample {
public static class Student {
public String name;
public String date;
public Student(String name, String date) {
this.name = name;
this.date = date;
}
}
public static class StudentComparator implements Comparator<Student> {
@Override
public int compare(Student s, Student t) {
int f = s.name.compareTo(t.name);
return (f != 0) ? f : s.date.compareTo(t.date);
}
}
public static void main(String args[]) {
ArrayList<Student> l = new ArrayList<Student>(Arrays.asList(
new Student ("x","2010-10-5"),
new Student ("z","2010-10-15"),
new Student ("y","2010-10-05"),
new Student ("x","2010-10-1")
));
System.out.println("Unsorted");
for(Student s : l) {
System.out.println(s.name + " " + s.date);
}
Collections.sort(l, new StudentComparator());
System.out.println("Sorted");
for(Student s : l) {
System.out.println(s.name + " " + s.date);
}
}
}
Output of this is: 输出为:
Unsorted
x 2010-10-5
z 2010-10-15
y 2010-10-05
x 2010-10-1
Sorted
x 2010-10-1
x 2010-10-5
y 2010-10-05
z 2010-10-15
EDIT : This sorts the array list in place. 编辑 :这对数组列表进行排序。 You'd have to copy it first if you want it as a new list. 如果要将其作为新列表,则必须先复制它。
The methods you require are: 您需要的方法是:
Collections.sort(List<T>, Comparator<? super T>)
The first method can be used if your Student
class implements the Comparable
interface. 如果您的Student
类实现Comparable
接口,则可以使用第一种方法。 As a side note it's worth considering whether in fact your data should be stored in a sorted data structure such as a SortedMap
(eg TreeMap
implementation). 附带说明一下,值得考虑的是,实际上您的数据是否应该存储在排序的数据结构中,例如SortedMap
(例如TreeMap
实现)。
I've written a framework to sort natural language text representations of objects in locale-sensitive order: 我编写了一个框架,以对语言环境敏感的顺序对对象的自然语言文本表示进行排序:
http://softsmithy.sourceforge.net/lib/docs/api/org/softsmithy/lib/text/Localizables.html http://softsmithy.sourceforge.net/lib/docs/api/org/softsmithy/lib/text/Localizables.html
Either Student would need to implement Localizable or you would have to provide a StudentLocalizer by extending Localizer . 学生将需要实现Localizable,或者您必须通过扩展Localizer提供一个StudentLocalizer。
Maven: Maven:
<dependency>
<groupId>org.softsmithy.lib</groupId>
<artifactId>lib-core</artifactId>
<version>0.1</version>
</dependency>
Download: 下载:
http://sourceforge.net/projects/softsmithy/files/softsmithy/v0.1/ http://sourceforge.net/projects/softsmithy/files/softsmithy/v0.1/
A test implementation could be: 测试实现可以是:
import java.util.ArrayList;
import java.util.Collections;
import java.util.List;
public class Execute {
public static void main(String args[]) {
List<Student> list = new ArrayList<Student>();
list.add(new Student("TestX"));
list.add(new Student("TestA"));
System.out.println(list);
Collections.sort(list);
System.out.println(list);
}
}
class Student implements Comparable<Student> {
private String name;
public Student() {
super();
}
public Student(String name) {
super();
this.name = name;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
@Override
public int compareTo(Student student) {
if (this.name == null || student.name == null) {
return 0;
}
return name.compareTo(student.name);
}
@Override
public String toString() {
return name;
}
}
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