PHP，继续; on foreach（）{foreach（）{

Question

Is there a way to continue on external foreach in case that the internal foreach meet some statement ?

In example

foreach($c as $v)
{
    foreach($v as $j)
    {
        if($j = 1)
        {
            continue; // But not the internal foreach. the external;
        }
    }
}

Answer 1

Try this, should work:

continue 2;

From the PHP Manual:

Continue accepts an optional numeric argument which tells it how many levels of enclosing loops it should skip to the end of.

here in the examples (2nd exactly) described code you need

Answer 2

Try this: continue 2; According to manual:

continue accepts an optional numeric argument which tells it how many levels of enclosing loops it should skip to the end of. 

Answer 3

There are two solutions available for this situation, either use break or continue 2 . Note that when using break to break out of the internal loop any code after the inner loop will still be executed.

foreach($c as $v)
{
    foreach($v as $j)
    {
        if($j = 1)
        {
            break;
        }
    }
    echo "This line will be printed";
}

The other solution is to use continue followed with how many levels back to continue from.

foreach($c as $v)
{
    foreach($v as $j)
    {
        if($j = 1)
        {
            continue 2;
        }
    }
    // This code will not be reached.
}

Answer 4

这将继续高于水平（所以外部的foreach）

 continue 2

Answer 5

<?php
foreach($c as $v)
{
    foreach($v as $j)
    {
        if($j = 1)
        {
            continue 2; // note the number 2
        }
    }
}
?>

RTM

Answer 6

Try break instead of continue .

You can follow break with an integer, giving the number of loops to break out of.

Answer 7

you have to use break instead of continue, if I get you right

Here I wrote an explanation on the matter: What is meant by a number after "break" or "continue" in PHP?