在Visual Studio中搜索和替换

Question

In Visual Studio, when I search within a selection, I want to replace the first instance (or second, third, etc.) of a match per line using regular expressions. How would I do this?

Search and replace

foo1 = foo1;
foo2 = foo2;
...
foo20 = foo20;

into the following.

foo1 = bar1;
foo2 = bar2;
...
foo20 = bar20;

Answer 1

In Visual Studio 2012, capture groups and backreferences are used just like in C#. You can capture them with common parenthesis, and backreference them with $0, $1, etc. Hope it helps!

Note that the syntax $1 is used for find-replace, but \\1 is used for backreferences in the search string.

Answer 2

In Visual Studio 2010 and earlier , use regular expressions with back references

Visual Studio's regular expressions are completely different from what I've learned. Took me some time to figure out the correct answer.

Search for

{foo}{:d+} = \1\2

Replace with

\1\2 = bar\2

Back references are done by tagging with curly braces {foo} . :d+ is the same for \\d+

Read more about VS RegEx here

Answer 3

Here it is, type exactly as it is displayed here

Search: (\\w+\\d+\\s*=\\s*)[^\\d]+(\\d+);

Replace: $1bar$2;

---

Read more: Using Regular Expressions in Visual Studio

Answer 4

As simple as this in Visual Studio 2019 Find/Replace. I needed to replace FORTRAN IO format string to C++ format and used sub-expression and numbers of regexp.

Example: find: "f9.8", "f18.3", in line and replace with %9.8f, %18.3f
reg exp: Find = ( f)(\\d+.\\d+) Replace = %$2f

Answer 5

I can be done without a regular expression as well:

Replace = foo with = bar .

If a regular expression is needed, one could use:

foo(\d*) = foo(\d*);

Replace with:

foo\1 = bar\2;

Answer 6

If you would be more variable:

Regex.Replace(input, @"(?<=\= )[^;0-9]*(?=[0-9]*;)", replacewith);

This search for = and (anynumber); and replace that between.

Edit: The number is optional.