[英]Mysql left join with another table with passed variable
I have 2 tables named projects
and tracklines
Every project can have multiple tracklines. 我有2个表分别命名为
projects
和tracklines
每个项目可以有多个跟踪线。
I have an SQL statement that will loop through my projects, but I want to be able to JOIN the trackline table with only 1 row. 我有一条将遍历我的项目的SQL语句,但我希望能够仅用1行加入跟踪线表。 What I want to do is get all tracklines that are part of a project, order them based on more than one field and do a LIMIT 1 on it so that I have one trackline which I'm joining with my project.
我要做的是获取项目中所有的跟踪线,基于多个字段对它们进行排序,并对其进行LIMIT 1,这样我就有一条要加入到我的项目中的跟踪线。
This is what I have so far: 这是我到目前为止的内容:
SELECT Project.* FROM `project` AS `Project`
LEFT JOIN (
SELECT *
FROM `trackline`
WHERE `trk_deleted` = '0'
ORDER BY `trk_state`, `trk_status`
LIMIT 1
) t ON t.`trk_project` = `prj_id`
ORDER BY `prj_name`
The problem is that I am not getting the trk_state
and trk_status
values in my outer query. 问题是我在外部查询中没有得到
trk_state
和trk_status
值。
I was thinking that my subquery could have WHERE trk_project
= prd_id
but I am not sure how to get that to happen. 我当时在想我的子查询可能有WHERE
trk_project
= prd_id
但是我不确定如何使这种情况发生。
You need to pull values from that derived table as well: 您还需要从该派生表中提取值:
SELECT Project.*, t.*
FROM ...
right now it's retrieving ONLY the fields from the Project table. 现在,它仅从Project表中检索字段。
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