如何将字符串转换为const char

Question

so i got that first problem working. i run the code and i am prompt to enter some list into the array. after entering the list i run this function as a search_func. but it keeps return no record found. is it because of [0], odd because i have it within a for loop.

Please help. book books[] is a class object..

int search(book books[], char search) {
    const char* boook =books[0].gettitle();
  //......try this but it failed please help
  cout << "Search books by title:____  ";

  cin >> search;

  bool yes = false;
  int size=2;

  for(int index=0; index<size; index++) {
    if(strcmp(boook,search) == 0 )//....error at this line
         { 
        found = true;
        cout<<"book found "<<endl;
        //cout<<"Author Name: "<<fn<<" "<<ln<<endl;
        break;
      }
  }

  if(!yes)
    cout<<"no book found"<<endl;
}

Answer 1

Try this:

const char* c_str = books[0].gettitle().c_str();

http://www.cplusplus.com/reference/string/string/c_str/

EDIT:

If gettitle() returns a temporary, then the above method won't work. You will need to do this instead:

string title = books[0].gettitle();
const char* c_str = title.c_str();

Answer 2

I am assuming the first argument is a std::string. Try calling it's c_str() method.