class_eval如何将参数传递给方法

Question

How do I pass the parameter name in the following case..the name is being is evaluated before being passed to class_eval

class Foo

end

Foo.class_eval %Q{
def hello(name)
 p "hello #{name}"
end
}

Sorry about not giving the entire scenario... I just wanted to add a instance method dynamically to a class and that method should be able to take arguments... the above code would not compile complaining that the name is not defined as local variable when executing in irb..

Thanks

Answer 1

The other answers are the "right" answer, but you could also just skip interpolating inside the p call:

Foo.class_eval %Q{
  def hello(name)
    p "hello \#{name}"
  end
}

I thought you wanted to change the actual parameter name (possibly useful for completion or when using Pry on dynamic methods), here assuming it's in a global, but could also be passed into a method doing the class_eval :

Foo.class_eval %Q{
  def hello(#{$argname})
    p "hello \#{$argname}"
  end
}

Answer 2

Really simple:

Foo.class_eval do
    def hello(name)
        p "hello #{name}"
    end
end

Answer 3

Try passing a block to class_eval instead of an array ( from this link ):

class Foo
end

Foo.class_eval {
  def hello(name)
    p "hello #{name}"
  end
}

You then can call the instance method hello in the usual fashion:

boo = Foo.new
boo.hello("you")

which produces:

>> boo.hello("you")
"hello you"
=> nil

Answer 4

class Foo
end

Foo.class_eval do
  define_method :hello do |name|
    p "hello #{name}"
  end
end

Foo.new.hello("coool") # => "hello coool"