[英]Read Child nodes including text and node using XPath from XElement ? LinQ
Using old way of doing via XmlDocument, 使用通过XmlDocument执行的旧方法,
string xmlstring = "<root><profile><Name>John</Name><Age>23</Age></profile></root>";
XmlDocument xmlDoc = new XmlDocument();
xmlDoc.LoadXml(xmlstring);
string childNodes = xmlDoc.SelectSingleNode("root/Profile").InnerXml;
// output of childNodes would be => "<Name>John</Name><Age>23</Age>";
what is the equivalent of doing the above execution in LinQ when you have XElement variable. 当您拥有XElement变量时,相当于在LinQ中执行上述执行。 I see XPathSelectElement method in XElement but it doesn't return the child nodes + Child nodes text.
我在XElement中看到XPathSelectElement方法,但它不返回子节点+子节点文本。 Any Ideas?
有任何想法吗?
I wouldn't use XPath at all for this. 我根本不会使用XPath。 I'd use:
我用的是:
XDocument doc = XDocument.Parse(xmlString);
var nodes = doc.Root
.Elements("profile")
.DescendantsAndSelf();
That give the profile
nodes and all their descendants. 这给了
profile
节点及其所有后代。 It's not really clear what you're trying to do with the results, but if you can give more details I should be able to come up with the appropriate code. 你要对结果做什么并不是很清楚,但是如果你能提供更多细节,我应该能够提出适当的代码。
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