计算文件中令牌的出现次数

Question

I have a server access log, with timestamps of each http request, I'd like to obtain a count of the number of requests at each second. Using sed , and cut -c , so far I've managed to cut the file down to just the timestamps, such as:

22-Sep-2008 20:00:21 +0000
22-Sep-2008 20:00:22 +0000
22-Sep-2008 20:00:22 +0000
22-Sep-2008 20:00:22 +0000
22-Sep-2008 20:00:24 +0000
22-Sep-2008 20:00:24 +0000

What I'd love to get is the number of times each unique timestamp appears in the file. For example, with the above example, I'd like to get output that looks like:

22-Sep-2008 20:00:21 +0000: 1
22-Sep-2008 20:00:22 +0000: 3
22-Sep-2008 20:00:24 +0000: 2

I've used sort -u to filter the list of timestamps down to a list of unique tokens, hoping that I could use grep like

grep -c -f <file containing patterns> <file>

but this just produces a single line of a grand total of matching lines.

I know this can be done in a single line, stringing a few utilities together ... but I can't think of which. Anyone know?

Answer 1

I think you're looking for

uniq --count

-c, --count prefix lines by the number of occurrences

Answer 2

将AWK与关联数组一起使用可能是另类解决方案。

Answer 3

以防万一您希望以最初指定的格式输出（最后出现的数量）：

uniq -c logfile | sed 's/\([0-9]+\)\(.*\)/\2: \1/'

Answer 4

Using awk :

cat file.txt | awk '{count[$1 " " $2]++;} \
                    END {for(w in count){print w ": " count[w]};}'

Answer 5

Tom's solution:

awk '{count[$1 " " $2]++;} END {for(w in count){print w ": " count[w]};}' file.txt

works more generally.

My file was not sorted :

name1 
name2 
name3 
name2 
name2 
name3 
name1

Therefore the occurrences weren't following each other, and uniq does not work as it gives :

1 name1 
1 name2 
1 name3 
2 name2 
1 name3 
1 name1

With the awk script however:

name1:2 
name2:3 
name3:2

Answer 6

maybe use xargs? Can't put it all together in my head on the spot here, but use xargs on your sort -u so that for each unique second you can grep the original file and do a wc -l to get the number.