[英]How to find all instances of @[XX:XXXX] in a string and then find the surrounding text?
Given a string like: 给定一个像这样的字符串:
"@[19:Sara Mas] what's the latest with the TPS report? @[30:Larry Peters] can you help out here?"
I want to find a way to dynamically return, the user tagged and the content surrounding. 我想找到一种动态返回,标记用户和周围内容的方法。 Results should be:
结果应该是:
user_id: 19
copy: what's the latest with the TPS report?
user_id: 30
copy: can you help out here?
Any ideas on how this can be done with ruby/rails? 关于如何使用红宝石/铁轨有什么想法? Thanks
谢谢
How is this regex for finding matches? 这个正则表达式如何找到匹配?
@\[\d+:\w+\s\w+\]
Split the string, then handle the content iteratively. 拆分字符串,然后迭代处理内容。 I don't think it'd take more than:
我认为这不仅仅需要:
tmp = string.split('@').map {|str| [str[/\[(\d*).*/,1], str[/\](.*^)/,1]] }
tmp.first #=> ["19", "what's the latest with the TPS report?"]
Does that help? 这有帮助吗?
result = subject.scan(/\[(\d+).*?\](.*?)(?=@|\Z)/m)
This grabs id and content in backreferences 1 and 2 respectively. 这分别在后向引用1和2中获取id和内容。 For stoping the capture either @ or the end of string must be met.
要停止捕获,必须满足@或字符串结尾。
"
\\[ # Match the character “[” literally
( # Match the regular expression below and capture its match into backreference number 1
\\d # Match a single digit 0..9
+ # Between one and unlimited times, as many times as possible, giving back as needed (greedy)
)
. # Match any single character that is not a line break character
*? # Between zero and unlimited times, as few times as possible, expanding as needed (lazy)
\\] # Match the character “]” literally
( # Match the regular expression below and capture its match into backreference number 2
. # Match any single character that is not a line break character
*? # Between zero and unlimited times, as few times as possible, expanding as needed (lazy)
)
(?= # Assert that the regex below can be matched, starting at this position (positive lookahead)
# Match either the regular expression below (attempting the next alternative only if this one fails)
\@ # Match the character “\@” literally
| # Or match regular expression number 2 below (the entire group fails if this one fails to match)
\$ # Assert position at the end of the string (or before the line break at the end of the string, if any)
)
"
This will match something starting from @ and ending to punctuation makr. 这将匹配从@开头到标点符号makr的内容。 Sorry if I didn't understand correctly.
对不起,如果我没有正确理解。
result = subject.scan(/@.*?[.?!]/)
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