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Scala 中下划线的所有用途是什么?

[英]What are all the uses of an underscore in Scala?

I've taken a look at the list of surveys taken on scala-lang.org and noticed a curious question: " Can you name all the uses of “_”? ".我查看scala-lang.org上的调查列表,注意到一个奇怪的问题:“你能说出“_”的所有用法吗? ”。 Can you?你是否可以? If yes, please do so here.如果是,请在此处执行。 Explanatory examples are appreciated.解释性示例表示赞赏。

The ones I can think of are我能想到的有

Existential types存在类型

def foo(l: List[Option[_]]) = ...

Higher kinded type parameters更高级的类型参数

case class A[K[_],T](a: K[T])

Ignored variables忽略的变量

val _ = 5

Ignored parameters忽略的参数

List(1, 2, 3) foreach { _ => println("Hi") }

Ignored names of self types忽略自身类型的名称

trait MySeq { _: Seq[_] => }

Wildcard patterns通配符模式

Some(5) match { case Some(_) => println("Yes") }

Wildcard patterns in interpolations插值中的通配符模式

"abc" match { case s"a$_c" => }

Sequence wildcard in patterns模式中的序列通配符

C(1, 2, 3) match { case C(vs @ _*) => vs.foreach(f(_)) }

Wildcard imports通配符导入

import java.util._

Hiding imports隐藏进口

import java.util.{ArrayList => _, _}

Joining letters to operators加入给运营商的信

def bang_!(x: Int) = 5

Assignment operators赋值运算符

def foo_=(x: Int) { ... }

Placeholder syntax占位符语法

List(1, 2, 3) map (_ + 2)

Method values方法值

List(1, 2, 3) foreach println _

Converting call-by-name parameters to functions将按名称调用的参数转换为函数

def toFunction(callByName: => Int): () => Int = callByName _

Default initializer默认初始化程序

var x: String = _   // unloved syntax may be eliminated

There may be others I have forgotten!可能还有其他我忘记了!


Example showing why foo(_) and foo _ are different:显示为什么foo(_)foo _不同的示例:

This example comes from 0__ :这个例子来自 0__

trait PlaceholderExample {
  def process[A](f: A => Unit)

  val set: Set[_ => Unit]

  set.foreach(process _) // Error 
  set.foreach(process(_)) // No Error
}

In the first case, process _ represents a method;第一种情况, process _代表一个方法; Scala takes the polymorphic method and attempts to make it monomorphic by filling in the type parameter, but realizes that there is no type that can be filled in for A that will give the type (_ => Unit) => ?阶取多晶型的方法和尝试以通过在类型参数填充以使其单形,但认识到没有任何类型,可在填充于A ,这将使类型(_ => Unit) => ? (Existential _ is not a type). (存在_不是一种类型)。

In the second case, process(_) is a lambda;在第二种情况下, process(_)是一个 lambda; when writing a lambda with no explicit argument type, Scala infers the type from the argument that foreach expects, and _ => Unit is a type (whereas just plain _ isn't), so it can be substituted and inferred.当编写一个没有显式参数类型的 lambda 时,Scala 从foreach期望的参数推断类型,并且_ => Unit一种类型(而只是普通的_不是),所以它可以被替换和推断。

This may well be the trickiest gotcha in Scala I have ever encountered.这很可能是我在 Scala 中遇到的最棘手的问题。

Note that this example compiles in 2.13.请注意,此示例在 2.13 中编译。 Ignore it like it was assigned to underscore.忽略它,就像它被分配给下划线一样。

From (my entry) in the FAQ , which I certainly do not guarantee to be complete (I added two entries just two days ago):来自FAQ中的(我的条目),我当然不保证它是完整的(我两天前添加了两个条目):

import scala._    // Wild card -- all of Scala is imported
import scala.{ Predef => _, _ } // Exception, everything except Predef
def f[M[_]]       // Higher kinded type parameter
def f(m: M[_])    // Existential type
_ + _             // Anonymous function placeholder parameter
m _               // Eta expansion of method into method value
m(_)              // Partial function application
_ => 5            // Discarded parameter
case _ =>         // Wild card pattern -- matches anything
val (a, _) = (1, 2) // same thing
for (_ <- 1 to 10)  // same thing
f(xs: _*)         // Sequence xs is passed as multiple parameters to f(ys: T*)
case Seq(xs @ _*) // Identifier xs is bound to the whole matched sequence
var i: Int = _    // Initialization to the default value
def abc_<>!       // An underscore must separate alphanumerics from symbols on identifiers
t._2              // Part of a method name, such as tuple getters
1_000_000         // Numeric literal separator (Scala 2.13+)

This is also part of this question .这也是这个问题的一部分。

An excellent explanation of the uses of the underscore is Scala _ [underscore] magic .下划线用法的一个很好的解释是Scala _ [underscore] magic

Examples:例子:

 def matchTest(x: Int): String = x match {
     case 1 => "one"
     case 2 => "two"
     case _ => "anything other than one and two"
 }

 expr match {
     case List(1,_,_) => " a list with three element and the first element is 1"
     case List(_*)  => " a list with zero or more elements "
     case Map[_,_] => " matches a map with any key type and any value type "
     case _ =>
 }

 List(1,2,3,4,5).foreach(print(_))
 // Doing the same without underscore: 
 List(1,2,3,4,5).foreach( a => print(a))

In Scala, _ acts similar to * in Java while importing packages.在 Scala 中, _在导入包时的作用类似于 Java 中的*

// Imports all the classes in the package matching
import scala.util.matching._

// Imports all the members of the object Fun (static import in Java).
import com.test.Fun._

// Imports all the members of the object Fun but renames Foo to Bar
import com.test.Fun.{ Foo => Bar , _ }

// Imports all the members except Foo. To exclude a member rename it to _
import com.test.Fun.{ Foo => _ , _ }

In Scala, a getter and setter will be implicitly defined for all non-private vars in a object.在 Scala 中,将为对象中的所有非私有变量隐式定义 getter 和 setter。 The getter name is same as the variable name and _= is added for the setter name. getter 名称与变量名称相同,并且为 setter 名称添加了_=

class Test {
    private var a = 0
    def age = a
    def age_=(n:Int) = {
            require(n>0)
            a = n
    }
}

Usage:用法:

val t = new Test
t.age = 5
println(t.age)

If you try to assign a function to a new variable, the function will be invoked and the result will be assigned to the variable.如果您尝试将函数分配给新变量,则会调用该函数并将结果分配给该变量。 This confusion occurs due to the optional braces for method invocation.这种混淆是由于方法调用的可选大括号造成的。 We should use _ after the function name to assign it to another variable.我们应该在函数名后使用 _ 将其分配给另一个变量。

class Test {
    def fun = {
        // Some code
    }
    val funLike = fun _
}

There is one usage I can see everyone here seems to have forgotten to list...有一种用法我看到这里的每个人似乎都忘记列出......

Rather than doing this:而不是这样做:

List("foo", "bar", "baz").map(n => n.toUpperCase())

You could can simply do this:你可以简单地这样做:

List("foo", "bar", "baz").map(_.toUpperCase())

Here are some more examples where _ is used:以下是使用_更多示例:

val nums = List(1,2,3,4,5,6,7,8,9,10)

nums filter (_ % 2 == 0)

nums reduce (_ + _)

nums.exists(_ > 5)

nums.takeWhile(_ < 8)

In all above examples one underscore represents an element in the list (for reduce the first underscore represents the accumulator)在上述所有示例中,一个下划线表示列表中的一个元素(为了减少第一个下划线表示累加器)

Besides theusages that JAiro mentioned, I like this one:除了 JAiro 提到的用法,我喜欢这个:

def getConnectionProps = {
    ( Config.getHost, Config.getPort, Config.getSommElse, Config.getSommElsePartTwo )
}

If someone needs all connection properties, he can do:如果有人需要所有连接属性,他可以这样做:

val ( host, port, sommEsle, someElsePartTwo ) = getConnectionProps

If you need just a host and a port, you can do:如果你只需要一个主机和一个端口,你可以这样做:

val ( host, port, _, _ ) = getConnectionProps
import scala._    // Wild card -- all of Scala is imported

import scala.{ Predef => _, _ } // Exclusion, everything except Predef

def f[M[_]]       // Higher kinded type parameter

def f(m: M[_])    // Existential type

_ + _             // Anonymous function placeholder parameter

m _               // Eta expansion of method into method value

m(_)              // Partial function application

_ => 5            // Discarded parameter

case _ =>         // Wild card pattern -- matches anything

f(xs: _*)         // Sequence xs is passed as multiple parameters to f(ys: T*)

case Seq(xs @ _*) // Identifier xs is bound to the whole matched sequence

Please check the below link for more details

[https://docs.scala-lang.org/tutorials/FAQ/finding-symbols.html][1]

There is a specific example that "_" be used:有一个使用“_”的具体示例:

  type StringMatcher = String => (String => Boolean)

  def starts: StringMatcher = (prefix:String) => _ startsWith prefix

may be equal to :可能等于:

  def starts: StringMatcher = (prefix:String) => (s)=>s startsWith prefix

Applying “_” in some scenarios will automatically convert to “(x$n) => x$n ”在某些情况下应用“_”会自动转换为“(x$n) => x$n ”

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