正则表达式从行首删除/ *…* /注释

Question

I have some files of this type:

/*  78 */     Lorem ipsum dolor sit amet   
/*  79 */     Lorem ipsum dolor sit amet   
/*  eb */     Lorem ipsum dolor sit amet   
/*  HG */     Lorem ipsum dolor sit amet   
/*     */     Lorem ipsum dolor sit amet  
/*  83 */     Lorem ipsum dolor sit amet   
/*  84 */     Lorem ipsum dolor sit amet  
/*     */ 
/*     */     Lorem ipsum dolor sit amet  
/*  ZX */     Lorem ipsum dolor sit amet  
/*     */     Lorem ipsum dolor sit amet  
/*     */     Lorem ipsum dolor sit amet  
/*  90 */     Lorem ipsum dolor sit amet  
/*  91 */     Lorem ipsum dolor sit amet  
/*  92 */     Lorem ipsum dolor sit amet  

And I want to eliminate the

/*    */ 
/* 10 */ 

parts of text with regex, my regex looks like:

[/*(0-9)*/]

but it's not working properly, it deletes some texts containing numbers

Answer 1

Everything inside [ and ] is called a character class , which will always match just a single character.

Inside a character class, the normal regex-meta-chars, like * , ( and ) , loose their special powers. So [*] matches just the literal '*' .

In your case, [/*(0-9)*/] will match one of the following chars: '/' , '*' , '(' , ')' , '/' or any (ASCII) digit.

What you're looking for is the regex:

(?m)^/\*[\s0-9]*\*/

which matches a "/*" followed by zero or more space-chars ( \\s ) or digits ( 0-9 ), ending with "*/" . The ^ matches the start of the input, and adding a (?m) in front of it makes it match the start of a line.

So it matches all multi-line comments from your example, except these:

/*  eb */
/*  HG */
/*  ZX */

Answer 2

Try this expression

/^\/\*[0-9\s]*\*\//

Or this expression if you want also to delete /* AH */

/^\/\*[\w\s]*\*\//

Answer 3

请尝试此操作，它使开始和结束/ *和* /与中间的一些文本匹配。

/^\/\*.*?\*\//

Answer 4

尝试使用以下正则表达式：

/\/\*.*?\*\//

Answer 5

Try this regular expression

\/\*.*?\*\/\s+

\\/\\* matches the starting / and *

.*? matches any amount of text without being greedy

\\*\\/ matches the ending * and /

\\s+ matches any amount of white space characters (optional)

Answer 6

If you're on Linux (or have access to it), you can do without regexes:

cut -b 10- <INPUTFILE>

Or if the strint is fixed width and on the beginngin of the line, with eg sed :

sed '/^.\{10\}//' <INPUTFILE>

Or with awk (if there are only two / on a line:

awk '{ print gensub(".*/","",1,$0) }'

HTH