在RegEx中接受国际名称字符

Question

I've always struggled with RegEx so forgive me if this may seem like an awful approach at tackling my problem.

When users are entering first and last names I started off just using the basic, check for upper and lower case, white space, apostrophes and hyphens

if (!preg_match("/^[a-zA-Z\s'-]+$/", $name)) { // Error }

Now I realise this isn't the best since people could have things such as: Dr. Martin Luther King, Jr. (with comma's and fullstops). So I assume by changing it to this would make it slightly more effective.

if (!preg_match("/^[a-zA-Z\s,.'-]+$/", $name)) { // Error }

I then saw a girls name I know on my Facebook who writes her name as Siân, which got me thinking of names which contain umlauts as well as say Japanese/Chinese/Korean/Russian characters too. So I started searching and found ways by writing each of these characters in there like so.

if (!preg_match("/^[a-zA-Z\sàáâäãåèéêëìíîïòóôöõøùúûüÿýñçčšžÀÁÂÄÃÅÈÉÊËÌÍÎÏÒÓÔÖÕØÙÚÛÜŸÝÑßÇŒÆČŠŽ∂ð ,.'-]+$/u", $first_name)) { // Error }

As you can imagine, it's extremely long winded and I'm pretty certain there is a much simpler RegEx which can achieve this. Like I've said, I've searched around but this is the best I can do.

So, what is a good way to check for upper and lower case characters, commas, full stops, apostrophes, hypens, umlauts, Latin, Japanese/Russian etc

Answer 1

You can use an Unicode character class. \\pL covers pretty much all letter symbols.
http://php.net/manual/en/regexp.reference.unicode.php

 if (!preg_match("/^[a-zA-Z\s,.'-\pL]+$/u", $name))

See also http://www.regular-expressions.info/unicode.html , but beware that PHP/PCRE only understands the abbreviated class names.

Answer 2

\\pL already includes az and AZ , therefore the mentioned pattern "/^[a-zA-Z\\s,.'-\\pL]+$/u" could be simplified to

"/^[\\s,.'-\\pL]+$/"

also the modifier u is not required.

Answer 3

There could probably be some loosening of the qualifications by allowing other types of punctuation.

One thing that should be a restriction is requiring at least one letter.

if (!preg_match("/^[\\s,.'-]*\\p{L}[\\p{L}\\s,.'-]*$/u", $name))