我使用json_decode有什么问题？

Question

I have a simple form with buttons and i am using jQuery and an ajax call to save.php. The dataType is set to json.

In save.php i use $selections= json_encode($_POST['selections']);

The $selections are stored in a mysql column selections (which i thinks is in JSON format)

[{"arrA":["a1","a3","a5","a8"]},{"arrB":["a1","a8"]},{"arrC":["a1"]}]

Now in show.php i like to parse the arrays and i manage to do this with

$test = json_decode($row['selections']); echo 'Array A: '.$test[0]->arrA[0]. ' |'.$test[0]->arrA[1]. ' |'.$test[0]->arrA[2]. ' |'.$test[0]->arrA[3].'<br/>';

I have the feeling i am doing something wrong, do you see it?

regards

Answer 1

我不确定您的问题是什么，但请尝试使用

$test = json_decode($row['selections'], true);