使用xslt替换根节点的xmlns属性

Question

I have xml like below

<rnp xmsns="v1">
  <ele1 line="1">
    <ele2></ele2>
  </ele1>
</rnp>

I want to change it to

<rnp xmsns="v2">
  <ele1 line="1">
    <ele2></ele2>
  </ele1>
</rnp>

using xslt 1.0.

I am using below xsl.

<?xml version="1.0" encoding="iso-8859-1"?>

<xsl:stylesheet version="1.0" 
xmlns:xsl="http://www.w3.org/1999/XSL/Transform" 
xmlns="v2">
    <xsl:template match="*">
        <xsl:element name="{local-name()}">
            <xsl:apply-templates select="@*|*|node()"/>
        </xsl:element>
    </xsl:template>

    <xsl:template match="rnp">
        <rnp>
            <xsl:apply-templates select="*"/>
        </rnp>
    </xsl:template> 
</xsl:stylesheet>

But this xsl does not copy the attributes so line attribute is not generated in output.

sample output

<?xml version="1.0" encoding="UTF-8"?><rnp xmlns="v2"><ele1>1
        <ele2/>
      </ele1></rnp>

How to change only the text of xmlns attrbiute using xslt? Is there any other way to change xmlns using xslt? I have only option of xslt 1.0.

Thanks.

Answer 1

This transformation :

<xsl:stylesheet version="1.0"
 xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
 <xsl:output omit-xml-declaration="yes" indent="yes"/>
 <xsl:strip-space elements="*"/>

 <xsl:param name="pNS" select="'v2'"/>

 <xsl:template match="node()|@*">
     <xsl:copy>
       <xsl:apply-templates select="node()|@*"/>
     </xsl:copy>
 </xsl:template>

 <xsl:template match="*[true()]">
  <xsl:element name="{local-name()}" namespace="{$pNS}">
       <xsl:apply-templates select="node()|@*"/>
  </xsl:element>
 </xsl:template>
</xsl:stylesheet>

when applied on the provided XML document (corrected to make it in the namespace "v1" :

<rnp xmlns="v1">
  <ele1 line="1">
    <ele2></ele2>
  </ele1>
</rnp>

produces the wanted, correct result :

<rnp xmlns="v2">
   <ele1 line="1">
      <ele2/>
   </ele1>
</rnp>

Do note :

1. The desired new default namespace is passed to the transformation as an external parameter -- thus the smae transformation without any modification can be used in every case when the default namespace must be modified.

2. This unusual looking template match: <xsl:template match="*[true()]"> makes it possible to avoid the XSLT processors "recoverable ambiguity error" messages if we had coded it just as <xsl:template match="*"> and is shorter and more elegant than specifying a priority.

Answer 2

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" 
                xmlns="v2">
    <xsl:output method="xml" indent="yes"/>

    <xsl:template match="@* | node()">
        <xsl:copy>
            <xsl:apply-templates select="@* | node()"/>
        </xsl:copy>
    </xsl:template>

    <xsl:template match="*">
        <xsl:element name="{local-name()}">
            <xsl:apply-templates select="@* | node()"/>
        </xsl:element>
    </xsl:template>

</xsl:stylesheet>

Output:

<rnp xmlns="v2">
    <ele1 line="1">
        <ele2 />
    </ele1>
</rnp>