[英]Create a Javascript RegExp to find opening tags in HTML/php template
I'm trying to write a Javascript HTML/php parser which would extract all opening tags from a HTML/php source and return the type of tag and attributes with their values while at the same time monitoring whether the values/attributes should be evaluated from static text or php variables. 我正在尝试编写一个Javascript HTML / php解析器,它将从HTML / php源中提取所有开始标记,并返回标记和属性的类型及其值,同时监视是否应评估值/属性静态文本或php变量。 The problem is when I try to compose the Javascript RegExp pattern and more specifically certain rare cases.
问题是当我尝试编写Javascript RegExp模式时,更具体地说是某些罕见情况。 The RegExp I was able to come up with either involve negative lookbehind (to cope with the closing php tag - that is to match a closing bracket that is not preceded by a question mark) or fails in certain cases.
RegExp我能够提出任何涉及负面的lookbehind(以处理关闭的php标记 - 即匹配一个没有问号的结束括号)或在某些情况下失败。 The lookbehind version looks like:
lookbehind版本看起来像:
<[a-zA-Z]+.*?(?<!\?)>
...and works perfect except for my case which must avoid using lookbehind. ...除了我必须避免使用lookbehind的情况外,它的工作原理很完美。 A more Javascript friendly version would be:
更友好的Javascript版本是:
<[a-zA-Z]+((.(?!</)(?!<[a-zA-Z]+))*)?>
...which works except in this case: ......在这种情况下除外:
<option value="<?php echo $img; ?>"<?php echo ($hpb[$i]['image_filename']==$img?' selected="selected"':''); ?>><?php echo $img; ?></option>
Am I approaching the problem completely messed up or is the lookbehind really necessary in my case? 我是否完全搞砸了这个问题,或者在我的情况下真的有必要吗? Any help is greatly appreciated.
任何帮助是极大的赞赏。
Just make sure the last letter before the '>' is not a ?, using [^?]. 只需确保'>'之前的最后一个字母不是?,使用[^?]。 No lookaheads or -behinds needed.
不需要前瞻或后顾之忧。
<[a-zA-Z](.*?[^?])?>
the parentheses and the last ? 括号和最后? is to also match tags like
<b>
. 也是为了匹配像
<b>
这样的标签。
EDIT The solution didn't work for single character tags without attributes. 编辑该解决方案不适用于没有属性的单个字符标签。 So here is one that does:
所以这是一个做的:
<[a-zA-Z]+(>|.*?[^?]>)
更简单的答案是<[^ / ^>] +>
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