为什么python subprocess.Popen通过cmd.exe启动子进程？
[英]Why does python subprocess.Popen launch a subprocess through cmd.exe?
问题描述
I call subprocess like this: 
我这样称呼子进程：
command = 'c:\somepath\myexe.exe'
startupinfo = subprocess.STARTUPINFO()
startupinfo.dwFlags |= subprocess.STARTF_USESHOWWINDOW
p = subprocess.Popen(command, shell=False, startupinfo=startupinfo)
It appears that instead of launching myexe.exe directly, it goes through cmd.exe. 似乎不是直接启动myexe.exe，而是通过cmd.exe。 Can I avoid cmd.exe here? 我可以在这里避免使用cmd.exe吗？
1 个解决方案
解决方案1
3 2011-11-28 09:24:36
Iff you're using Python 2.7 - use subprocess._subprocess.STARTF_USESHOWWINDOW instead of subprocess.STARTF_USESHOWWINDOW. 如果您使用的是Python 2.7，请使用subprocess._subprocess.STARTF_USESHOWWINDOW而不是subprocess.STARTF_USESHOWWINDOW。 I think this would solve it. 我认为这可以解决。
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