从文件中提取数字

Question

I have a txt file " 80 50 65 100 2 35 1 " and i need to add each number in a Var or even better all of them in an array. like ...

var1=80 var2=50

or

array[0]=80

.by the way the number after that must be functional . I mean i need to be able to sum= $var1 +$var2 for example. Is there a way to do that ? Thank you!!

Answer 1

If your numbers are all on a line, use read

read -a array < numbers.txt

If they're on multiple lines you can change the end of line delimiter like this

read -d'\0' -a array < numbers.txt

And now you have an array

printf 'Number: %s\n' "${array[@]}"

Oh yeah, and summing. Lots of ways once you have an array, but how about

printf '%s + ' "${array[@]}" | xargs -I{} echo {} 0 | bc

Or do it all in one process

for n in "${array[@]}" ; do let sum+=$n ; done ; echo $sum

Answer 2

In bash, you can say

array=( $(< numbers.txt) )
sum=$( IFS=+; echo "${array[*]}" | bc )

Answer 3

So if you have a file nums.dat like

80 50 65 100 2 35 1

You can read these into an array with

read -a MYARRAY < nums.dat

If you have a much older bash or even ksh then it was something like (can't remember exactly sorry)

set -A MYARRAY $(cat nums.dat)