Bash测试并在目录模式存在时执行

Question

How do you do an inline test for the existence of a directory pattern?

If a directory pattern exists, then I want to chmod that pattern.

eg I'm trying to do the following:

[ -d /usr/local/myproject/*/bin ] && chmod +x /usr/local/myproject/*/bin/*

but this gives me the error "-bash: [: too many arguments".

Answer 1

没有必要测试：

chmod +x /usr/local/myproject/*/bin/* 2>/dev/null

Answer 2

It doesn't work because -d test takes one argument. You seem to be passing more than one. A fix would be:

for dir in /usr/local/myproject/*/bin; do
    [[ -d $dir ]] && chmod +x $dir/*
done

Answer 3

为了从我的答案中挽救一些有用的东西，假设你有太多的bin目录，你不能这样做yi_H的方式。

find /usr/local/myproject/ -path '/usr/local/myproject/*/bin' -maxdepth 2 -type d -exec chmod a+x {} + 2>/dev/null