使用PHP DOM-XPATH解析XML标签，而不会丢失内部标签和数据

Question

I want to parse data which looks similar to the following:

<table-wrap id ="T1">
<table-wrap-foot>
<fn>
<p>
Blah blah blah <strong>dsf</strong> blah blah blah <br>
</p>
</fn>
<table-wrap-foot>
<table-wrap>

When I call

$x = $xpath->query("//table-wrap-foot[@id='" . $tableAttributes . "']/p")->item(0);

I'll get the node of paragraph including tags and data inside along with the <p> tags.

$x = $xpath->query("//table-wrap-foot[@id='".$tableAttributes."']/p")->item(0)->nodeValue;

I'll get the data inside the

tags but it doesn't contain <strong> tag..

So my requirement is I need data along with tags inside excluding the <p> tags.

Is there any possibility to do that?

Answer 1

You could simply select the node() children of your p element and iterate the list. Taking your example expression at face value (although it doesn't match up to your sample input):

//table-wrap-foot[@id='".$tableAttributes."']/p/node()

Note that there are five such nodes:

#text 
strong
#text 
br
#text

Even more appropriate would be to select the union of these text and element nodes:

//table-wrap-foot[@id='".$tableAttributes."']/p/*|
//table-wrap-foot[@id='".$tableAttributes."']/p/text()