C＃运算符“ >> =”-它是如何工作的？

Question

I wonder what the ">>=" operator in C# does. Can anyone tell me?

Answer 1

It's the right-shift assignment operator. From MSDN:

An expression of the form

x >>= y

is evaluated as

x = x >> y

except that x is only evaluated once. The >> operator shifts x right by an amount specified by y.

>>= Operator (C# Reference)

Answer 2

x >>= y is the same as doing x = x >> y

It's just like += but with bit shifting operators.

Answer 3

Like C,

x >>= y

is the same as:

x = x >> y

This is similar to all the other op= operators like += and /= . The >> operator is bit shifting to the right.

For example, the variable x with decimal value 50 10 (in binary, 00110010 10 ) can be bit-shifted two bits right with:

x >>= 2

and it will become 00001100 2 , or 12 10 .

Answer 4

>>= is a bitshift to the "right". eg you have a integer variable containing the value 4. It is coded in binary 100. After the operation i >>= 1 the variable contains the value 2 (coded in binary 10).

 int i = 4;
 i >>= 1;
 // i is 2 now

Answer 5

"x >>= y" is equivalent to "x = x >> y"
see also:
http://sharpertutorials.com/c-operator-list/

Answer 6

x>>=y只是x = x >> y一种更短的表达方式...您将x向右移动y位。