[英]A simple Java code that returns unexpectedly false while it is intened to return true
The following simple code in Java contains hardly 3 statements that returns unexpectedly false though it looks like that it should return true . Java中的以下简单代码几乎不包含3个语句,这些语句意外返回false,尽管看起来它应该返回true 。
package temp;
final public class Main
{
public static void main(String[] args)
{
long temp = 2000000000;
float f=temp;
System.out.println(f<temp+50);
}
}
The above code should obviously display true on the console but it doesn't. 上面的代码显然应该在控制台上显示为true ,但事实并非如此。 It displays false instead.
它显示为false 。 Why?
为什么?
This happens because floating point arithmetic != real number arithmetic . 这是因为浮点运算!=实数运算 。
When f
is assigned 2000000000
, it gets converted to 2.0E9
. 当
f
被分配2000000000
,它将被转换为2.0E9
。 Then when you add 50 to 2.0E9
, its value doesn't change. 然后,当您将50添加到
2.0E9
,其值不会更改。 So actually, (f == temp + 50)
is true
. 实际上,
(f == temp + 50)
是true
。
If you need to work with large numbers but require precision, you'll have to use something like BigDecimal
: 如果你需要使用大数字但需要精度,你将不得不使用类似
BigDecimal
东西:
long temp = 2000000000;
BigDecimal d = new BigDecimal(temp);
System.out.println(d.compareTo(new BigDecimal(temp+50)) < 0);
Will print true
as one would expected. 将按照预期打印出
true
。
(although in your case I don't know why you'd need to use a datatype other than long
). (虽然在你的情况下我不知道为什么你需要使用除
long
之外的数据类型)。
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