[英]How to convert a char to a String?
I have a char
and I need a String
.我有一个
char
,我需要一个String
。 How do I convert from one to the other?如何从一个转换为另一个?
You can use Character.toString(char)
.您可以使用
Character.toString(char)
。 Note that this method simply returns a call to String.valueOf(char)
, which also works.请注意,此方法仅返回对
String.valueOf(char)
的调用,这也有效。
As others have noted, string concatenation works as a shortcut as well:正如其他人所指出的,字符串连接也可以作为一种快捷方式:
String s = "" + 's';
But this compiles down to:但这可以归结为:
String s = new StringBuilder().append("").append('s').toString();
which is less efficient because the StringBuilder
is backed by a char[]
(over-allocated by StringBuilder()
to 16
), only for that array to be defensively copied by the resulting String
.这效率较低,因为
StringBuilder
由char[]
(由StringBuilder()
过度分配到16
),仅用于由结果String
防御性复制该String
。
String.valueOf(char)
"gets in the back door" by wrapping the char
in a single-element array and passing it to the package private constructor String(char[], boolean)
, which avoids the array copy. String.valueOf(char)
通过将char
包装在单元素数组中并将其传递给包私有构造函数String(char[], boolean)
来“进入后门”,从而避免了数组复制。
I've got of the following
five
six methods to do it.我有以下
五
六种方法来做到这一点。
// Method #1
String stringValueOf = String.valueOf('c'); // most efficient
// Method #2
String stringValueOfCharArray = String.valueOf(new char[]{x});
// Method #3
String characterToString = Character.toString('c');
// Method #4
String characterObjectToString = new Character('c').toString();
// Method #5
// Although this approach seems very simple,
// this is less efficient because the concatenation
// expands to a StringBuilder.
String concatBlankString = 'c' + "";
// Method #6
String fromCharArray = new String(new char[]{x});
Note: Character.toString(char) returns String.valueOf(char) .
注意: Character.toString(char)返回String.valueOf(char) 。 So effectively both are same.
因此,两者实际上是相同的。
String.valueOf(char[] value)
invokes new String(char[] value)
, which in turn sets the value
char array. String.valueOf(char[] value)
调用new String(char[] value)
,它依次设置value
char 数组。
public String(char value[]) {
this.value = Arrays.copyOf(value, value.length);
}
On the other hand String.valueOf(char value)
invokes the following package private constructor.另一方面
String.valueOf(char value)
调用以下包私有构造函数。
String(char[] value, boolean share) {
// assert share : "unshared not supported";
this.value = value;
}
Source code from String.java
in Java 8 source code Java 8 源代码中来自
String.java
源代码
Hence
String.valueOf(char)
seems to be most efficient method, in terms of both memory and speed, for convertingchar
toString
.因此
String.valueOf(char)
在内存和速度方面似乎是将char
转换为String
最有效方法。
Sources:资料来源:
Below are various ways to convert to char c to String s (in decreasing order of speed and efficiency)以下是将 char c 转换为 String s 的各种方法(按速度和效率的降序排列)
char c = 'a';
String s = String.valueOf(c); // fastest + memory efficient
String s = Character.toString(c);
String s = new String(new char[]{c});
String s = String.valueOf(new char[]{c});
String s = new Character(c).toString();
String s = "" + c; // slowest + memory inefficient
Use the Character.toString()
method like so:像这样使用
Character.toString()
方法:
char mChar = 'l';
String s = Character.toString(mChar);
Use any of the following:使用以下任何一种:
String str = String.valueOf('c');
String str = Character.toString('c');
String str = 'c' + "";
As @WarFox stated - there are 6 methods to convert char to string.正如@WarFox 所说 - 有 6 种方法可以将字符转换为字符串。 However, the fastest one would be via concatenation, despite answers above stating that it is
String.valueOf
.然而,最快的方法是通过串联,尽管上面的答案指出它是
String.valueOf
。 Here is benchmark that proves that:这是证明这一点的基准:
@BenchmarkMode(Mode.Throughput)
@Fork(1)
@State(Scope.Thread)
@Warmup(iterations = 10, time = 1, batchSize = 1000, timeUnit = TimeUnit.SECONDS)
@Measurement(iterations = 10, time = 1, batchSize = 1000, timeUnit = TimeUnit.SECONDS)
public class CharToStringConversion {
private char c = 'c';
@Benchmark
public String stringValueOf() {
return String.valueOf(c);
}
@Benchmark
public String stringValueOfCharArray() {
return String.valueOf(new char[]{c});
}
@Benchmark
public String characterToString() {
return Character.toString(c);
}
@Benchmark
public String characterObjectToString() {
return new Character(c).toString();
}
@Benchmark
public String concatBlankStringPre() {
return c + "";
}
@Benchmark
public String concatBlankStringPost() {
return "" + c;
}
@Benchmark
public String fromCharArray() {
return new String(new char[]{c});
}
}
And result:结果:
Benchmark Mode Cnt Score Error Units
CharToStringConversion.characterObjectToString thrpt 10 82132.021 ± 6841.497 ops/s
CharToStringConversion.characterToString thrpt 10 118232.069 ± 8242.847 ops/s
CharToStringConversion.concatBlankStringPost thrpt 10 136960.733 ± 9779.938 ops/s
CharToStringConversion.concatBlankStringPre thrpt 10 137244.446 ± 9113.373 ops/s
CharToStringConversion.fromCharArray thrpt 10 85464.842 ± 3127.211 ops/s
CharToStringConversion.stringValueOf thrpt 10 119281.976 ± 7053.832 ops/s
CharToStringConversion.stringValueOfCharArray thrpt 10 86563.837 ± 6436.527 ops/s
As you can see, the fastest one would be c + ""
or "" + c
;如您所见,最快的是
c + ""
或"" + c
;
VM version: JDK 1.8.0_131, VM 25.131-b11
This performance difference is due to -XX:+OptimizeStringConcat
optimization.这种性能差异是由于
-XX:+OptimizeStringConcat
优化造成的。 You can read about it here .你可以在这里阅读它。
试试这个: Character.toString(aChar)
或者只是这个: aChar + ""
We have various ways to convert a char
to String
.我们有多种方法将
char
转换为String
。 One way is to make use of static method toString()
in Character
class:一种方法是在
Character
类中使用静态方法toString()
:
char ch = 'I';
String str1 = Character.toString(ch);
Actually this toString
method internally makes use of valueOf
method from String
class which makes use of char array:实际上这个
toString
方法在内部使用了String
类的valueOf
方法,它使用了 char 数组:
public static String toString(char c) {
return String.valueOf(c);
}
So second way is to use this directly:所以第二种方法是直接使用它:
String str2 = String.valueOf(ch);
This valueOf
method in String
class makes use of char array: String
类中的valueOf
方法使用了 char 数组:
public static String valueOf(char c) {
char data[] = {c};
return new String(data, true);
}
So the third way is to make use of an anonymous array to wrap a single character and then passing it to String
constructor:所以第三种方法是利用匿名数组来包装单个字符,然后将其传递给
String
构造函数:
String str4 = new String(new char[]{ch});
The fourth way is to make use of concatenation:第四种方式是利用concatenation:
String str3 = "" + ch;
This will actually make use of append
method from StringBuilder
class which is actually preferred when we are doing concatenation in a loop.这实际上将使用
StringBuilder
类的append
方法,当我们在循环中进行连接时,它实际上是首选。
Here are a few methods, in no particular order:这里有一些方法,没有特定的顺序:
char c = 'c';
String s = Character.toString(c); // Most efficient way
s = new Character(c).toString(); // Same as above except new Character objects needs to be garbage-collected
s = c + ""; // Least efficient and most memory-inefficient, but common amongst beginners because of its simplicity
s = String.valueOf(c); // Also quite common
s = String.format("%c", c); // Not common
Formatter formatter = new Formatter();
s = formatter.format("%c", c).toString(); // Same as above
formatter.close();
I am converting Char Array to String我正在将字符数组转换为字符串
Char[] CharArray={ 'A', 'B', 'C'};
String text = String.copyValueOf(CharArray);
char vIn = 'A';
String vOut = Character.toString(vIn);
For these types of conversion, I have site bookmarked called https://www.converttypes.com/ It helps me quickly get the conversion code for most of the languages I use.对于这些类型的转换,我有一个名为https://www.converttypes.com/ 的站点书签,它帮助我快速获取我使用的大多数语言的转换代码。
I've tried the suggestions but ended up implementing it as follows我已经尝试了这些建议,但最终按如下方式实施
editView.setFilters(new InputFilter[]{new InputFilter()
{
@Override
public CharSequence filter(CharSequence source, int start, int end,
Spanned dest, int dstart, int dend)
{
String prefix = "http://";
//make sure our prefix is visible
String destination = dest.toString();
//Check If we already have our prefix - make sure it doesn't
//get deleted
if (destination.startsWith(prefix) && (dstart <= prefix.length() - 1))
{
//Yep - our prefix gets modified - try preventing it.
int newEnd = (dend >= prefix.length()) ? dend : prefix.length();
SpannableStringBuilder builder = new SpannableStringBuilder(
destination.substring(dstart, newEnd));
builder.append(source);
if (source instanceof Spanned)
{
TextUtils.copySpansFrom(
(Spanned) source, 0, source.length(), null, builder, newEnd);
}
return builder;
}
else
{
//Accept original replacement (by returning null)
return null;
}
}
}});
The String class has a static method valueOf() that is designed for this particular use case. String 类具有专为此特定用例设计的静态方法 valueOf()。 Here you can see it in action:
在这里你可以看到它的实际效果:
public class CharToString {
public static void main(String[] args) {
char givenChar = 'c';
String result = String.valueOf(givenChar);
//check result value string or char
System.out.println(result.equals("c"));
System.out.println(result.equals(givenChar));
}
}
Output::输出::
true
false
We can also use the built-in method of Character class to convert a character to a String.我们还可以使用 Character 类的内置方法将字符转换为 String。
The below example illustrates this:下面的例子说明了这一点:
public class CharToString {
public static void main(String[] args) {
char givenChar = 'c';
String result = Character.toString(givenChar);
//check result value string or char
System.out.println(result.equals("c"));
System.out.println(result.equals(givenChar));
}
}
Output::输出::
true
false
This method simply concatenates the given character with an empty string to convert it to a String.此方法只是将给定的字符与空字符串连接起来,以将其转换为字符串。
The below example illustrates this:下面的例子说明了这一点:
public class CharToString {
public static void main(String[] args) {
char myChar = 'c';
String charToString = myChar + "";
//check result value string or char
System.out.println(charToString.equals("c"));
System.out.println(charToString.equals(myChar));
}
}
Output::输出::
true
false
However, this is the least efficient method of all since the seemingly simple concatenation operation expands to new StringBuilder().append(x).append("").toString();然而,这是效率最低的方法,因为看似简单的连接操作扩展为 new StringBuilder().append(x).append("").toString(); which is more time consuming than the other methods we discussed.
这比我们讨论的其他方法更耗时。
You could also instantiate Character object and use a standard toString() method:您还可以实例化 Character 对象并使用标准的 toString() 方法:
@Test
public void charToString() {
char givenChar = 'x';
String result = new Character(givenChar).toString();
assertThat(result).isEqualTo("x");
}
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