[英]Compare a map's value with another map value in groovy
I have a requirement where I want to check a map's value
with another map's value
if it matches I'd like to get the key
of 1st map 我有一个要求,如果我想获取第一张地图的
key
,我想和另一map's value
a map's value
一起检查a map's value
virtualization map 虚拟化地图
def virtua=[
"VMWARE" : "00:68:8B:",
"VMWARE" : "00:68:8A",
"COLINUX" : "00:18:8A:"
]
network map 网络图
def network=[
"eth0":"00:68:8B:",
"eth1":"00:18:8A:",
"eth2":"00:68:8A:"
]
So after matching values from network
& virtua
I get the below output, how can i do it in groovy? 因此,在从
network
& virtua
匹配值之后,我得到以下输出,如何在Groovy中做到这一点?
eth0,00:68:8B:,VMWARE
eth1,00:18:8A:,COLINUX
eth2,00:68:8A:,VMWARE
Update After @tim_yates & @Xaerxess answer, I thought it's best if I had MAC Addr as keys as VMWARE
can be duplicate 更新 @tim_yates和@Xaerxess回答后,我认为最好将MAC地址作为密钥,因为
VMWARE
可以复制
def virtua1=[
"00:68:8B:" : "VMWARE",
"00:68:8A:" : "VMWARE",
"00:18:8A:" : "COLINUX"
]
def coll = network.collect { k, v ->
//[ k, v, virtua.find { a, b -> b == v }?.key ]
print "$k,$v,"
println virtua1.find{ a, b -> a == v }?.value
}
Output 输出量
eth0,00:68:8B:,VMWARE
eth1,00:18:8A:,COLINUX
eth2,00:68:8A:,VMWARE
You can't have duplicate keys in a map (you have multiple VMWARE
entries), and your network variable is a list not a map... 映射中不能有重复的键(您有多个
VMWARE
条目),并且网络变量是列表而不是映射...
Correcting these, and assuming you mean: 更正这些,并假设您的意思是:
def virtua=[
"VMWAREA" : "00:68:8B:",
"VMWAREB" : "00:68:8A:",
"COLINUX" : "00:18:8A:"
]
def network=[
"eth0":"00:68:8B:",
"eth1":"00:18:8A:",
"eth2":"00:68:8A:",
]
you can do: 你可以做:
def coll = network.collect { k, v ->
[ k, v, virtua.find { a, b -> b == v }?.key ]
}
To give you the list: 为您提供清单:
[ ["eth0", "00:68:8B:", "VMWAREA"],
["eth1", "00:18:8A:", "COLINUX"],
["eth2", "00:68:8A:", "VMWAREB"] ]
And if you want that printed out as comma separated Strings, you can just do: 如果您希望将其打印为以逗号分隔的字符串,则可以执行以下操作:
coll*.join(',').each { println it }
In the comments, I was asked about a Map with values as Lists (to get around the duplicate key problem); 在评论中,有人问我一个映射,该映射具有作为列表的值(以解决重复键问题);
def virtua=[
"VMWARE" : [ "00:68:8B:", "00:68:8A:" ],
"COLINUX" : [ "00:18:8A:" ]
]
def network=[
"eth0":"00:68:8B:",
"eth1":"00:18:8A:",
"eth2":"00:68:8A:",
]
network.each { k, v ->
println "$k,$v,${virtua.find { it.value.grep( v ) }?.key}"
}
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