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将地图的值与Groovy中的另一个地图值进行比较

[英]Compare a map's value with another map value in groovy

I have a requirement where I want to check a map's value with another map's value if it matches I'd like to get the key of 1st map 我有一个要求,如果我想获取第一张地图的key ,我想和另一map's value a map's value一起检查a map's value

virtualization map 虚拟化地图

def virtua=[
    "VMWARE"        :   "00:68:8B:",
    "VMWARE"        :   "00:68:8A",
    "COLINUX"       :   "00:18:8A:"
]

network map 网络图

def network=[
    "eth0":"00:68:8B:",
    "eth1":"00:18:8A:",
    "eth2":"00:68:8A:"
]

So after matching values from network & virtua I get the below output, how can i do it in groovy? 因此,在从networkvirtua匹配值之后,我得到以下输出,如何在Groovy中做到这一点?

eth0,00:68:8B:,VMWARE
eth1,00:18:8A:,COLINUX
eth2,00:68:8A:,VMWARE

Update After @tim_yates & @Xaerxess answer, I thought it's best if I had MAC Addr as keys as VMWARE can be duplicate 更新 @tim_yates@Xaerxess回答后,我认为最好将MAC地址作为密钥,因为VMWARE可以复制

def virtua1=[
"00:68:8B:"     :   "VMWARE",
"00:68:8A:"     :   "VMWARE",
"00:18:8A:"     :   "COLINUX"
]

def coll = network.collect { k, v ->   
    //[ k, v, virtua.find { a, b -> b == v }?.key ]
    print "$k,$v,"
    println virtua1.find{ a, b -> a == v }?.value
}

Output 输出量

eth0,00:68:8B:,VMWARE
eth1,00:18:8A:,COLINUX
eth2,00:68:8A:,VMWARE

You can't have duplicate keys in a map (you have multiple VMWARE entries), and your network variable is a list not a map... 映射中不能有重复的键(您有多个VMWARE条目),并且网络变量是列表而不是映射...

Correcting these, and assuming you mean: 更正这些,并假设您的意思是:

def virtua=[
    "VMWAREA"       :   "00:68:8B:",
    "VMWAREB"       :   "00:68:8A:",
    "COLINUX"       :   "00:18:8A:"
]
def network=[
    "eth0":"00:68:8B:",
    "eth1":"00:18:8A:",
    "eth2":"00:68:8A:",
]

you can do: 你可以做:

def coll = network.collect { k, v ->
  [ k, v, virtua.find { a, b -> b == v }?.key ]
}

To give you the list: 为您提供清单:

[ ["eth0", "00:68:8B:", "VMWAREA"],
  ["eth1", "00:18:8A:", "COLINUX"],
  ["eth2", "00:68:8A:", "VMWAREB"] ]

And if you want that printed out as comma separated Strings, you can just do: 如果您希望将其打印为以逗号分隔的字符串,则可以执行以下操作:

coll*.join(',').each { println it }

Edit -- key:list example 编辑-键:列表示例

In the comments, I was asked about a Map with values as Lists (to get around the duplicate key problem); 在评论中,有人问我一个映射,该映射具有作为列表的值(以解决重复键问题);

def virtua=[
    "VMWARE"  : [ "00:68:8B:", "00:68:8A:" ],
    "COLINUX" : [ "00:18:8A:" ]
]
def network=[
    "eth0":"00:68:8B:",
    "eth1":"00:18:8A:",
    "eth2":"00:68:8A:",
]
network.each { k, v ->
  println "$k,$v,${virtua.find { it.value.grep( v ) }?.key}"
}

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