如何从List的每个元素中提取（在C＃中）特定属性，并获取这些属性的新列表？

Question

We begin with a List<X> . Every object of X has an attribute x of type Y. Could you propose an elegant way to construct a List which is composed of the Zx for every element Z of some List<X> ? I'm sure "manual" iteration over List<X> isn't necessary. Thanks for any advice.

Answer 1

If this is List<T> , then:

var newList = oldList.ConvertAll(item => item.x);

or with LINQ:

var newList = oldList.Select(item => item.x).ToList();

Note that in C# 2.0 the first version might need the generic type mentioned explicitly:

List<Y> newList = oldList.ConvertAll<Y>(delegate (X item) { return item.x; });

(but that is actually 100% identical to the first line)

There is also a static Array.ConvertAll which behaves similarly, but for arrays.