用awk或sed比较两个文件

Question

This must be easy for you

Here is file1 (one column)

1
2
3
4
5
6
7
8
9

and here is file2 (two columns)

2 yay
3 ups
4 wow
8 hey

There must be a simple one liner to print out lines in file1 that don´t match to file2

Answer 1

 awk 'NR==FNR{a[$1]++;next;}!($0 in a)' file2 file1

or using join with -v, as @Michael suggested:

join -v1 file1 file2

both will print :

1
5
6
7
9

Answer 2

You can do this by combining cut and comm :

cut -d' ' -f1 file2 | comm -13 - file1

You might also consider join , depending on how you want to handle repeated lines.

Answer 3

This sed solution might work for you:

{ seq 1 10; echo -e "2 yay\n3 ups\n4 wow\n8 hey"; } | sort -n | 
sed '1{h;d};H;${x;s/\(\S\+\)\n\1[^\n]*\n//g;p};d'
1
5
6
7
9
10

Explanation: Sort the files numerically then using sed slurp the file in to the hold space (HS). At end of file swap to the HS and then delete lines with the duplicate keys.