JavaScript 正则表达式匹配文本字段中的 URL

Question

How can I setup my regex to test to see if a URL is contained in a block of text in javascript. I cant quite figure out the pattern to use to accomplish this

 var urlpattern = new RegExp( "(http|ftp|https):\/\/[\w\-_]+(\.[\w\-_]+)+([\w\-\.,@?^=%&:/~\+#]*[\w\-\@?^=%&/~\+#])?"

 var txtfield = $('#msg').val() /*this is a textarea*/

 if ( urlpattern.test(txtfield) ){
        //do something about it
 }

EDIT:

So the Pattern I have now works in regex testers for what I need it to do but chrome throws an error

  "Invalid regular expression: /(http|ftp|https)://[w-_]+(.[w-_]+)+([w-.,@?^=%&:/~+#]*[w-@?^=%&/~+#])?/: Range out of order in character class"

for the following code:

var urlexp = new RegExp( '(http|ftp|https):\/\/[\w\-_]+(\.[\w\-_]+)+([\w\-\.,@?^=%&:/~\+#]*[\w\-\@?^=%&/~\+#])?' );

Answer 1

Though escaping the dash characters (which can have a special meaning as character range specifiers when inside a character class) should work, one other method for taking away their special meaning is putting them at the beginning or the end of the class definition.

In addition, \\+ and \\@ in a character class are indeed interpreted as + and @ respectively by the JavaScript engine; however, the escapes are not necessary and may confuse someone trying to interpret the regex visually.

I would recommend the following regex for your purposes:

(http|ftp|https)://[\w-]+(\.[\w-]+)+([\w.,@?^=%&:/~+#-]*[\w@?^=%&/~+#-])?

this can be specified in JavaScript either by passing it into the RegExp constructor (like you did in your example):

var urlPattern = new RegExp("(http|ftp|https)://[\w-]+(\.[\w-]+)+([\w.,@?^=%&:/~+#-]*[\w@?^=%&/~+#-])?")

or by directly specifying a regex literal, using the // quoting method:

var urlPattern = /(http|ftp|https):\/\/[\w-]+(\.[\w-]+)+([\w.,@?^=%&:\/~+#-]*[\w@?^=%&\/~+#-])?/

The RegExp constructor is necessary if you accept a regex as a string (from user input or an AJAX call, for instance), and might be more readable (as it is in this case). I am fairly certain that the // quoting method is more efficient, and is at certain times more readable. Both work.

I tested your original and this modification using Chrome both on < JSFiddle > and on < RegexLib.com >, using the Client-Side regex engine (browser) and specifically selecting JavaScript. While the first one fails with the error you stated, my suggested modification succeeds. If I remove the h from the http in the source, it fails to match, as it should!

Edit

As noted by @noa in the comments, the expression above will not match local network (non-internet) servers or any other servers accessed with a single word (eg http://localhost/ ... or https://sharepoint-test-server/ ...). If matching this type of url is desired (which it may or may not be), the following might be more appropriate:

(http|ftp|https)://[\w-]+(\.[\w-]+)*([\w.,@?^=%&:/~+#-]*[\w@?^=%&/~+#-])?

#------changed----here-------------^

< End Edit >

Finally, an excellent resource that taught me 90% of what I know about regex is Regular-Expressions.info - I highly recommend it if you want to learn regex (both what it can do and what it can't)!

Answer 2

Complete Multi URL Pattern.

UPDATED: Nov. 2020, April & June 2021 (Thanks commenters)

Matches all URI or URL in a string! Also extracts the protocol, domain, path, query and hash. ([a-z0-9-]+\\:\\/+)([^\\/\\s]+)([a-z0-9\\-@\\^=%&;\\/~\\+]*)[\\?]?([^ \\#\\r\\n]*)#?([^ \\#\\r\\n]*)

https://regex101.com/r/jO8bC4/56

Example JS code with output - every URL is turned into a 5-part array of its 'parts' (protocol, host, path, query, and hash)

var re = /([a-z0-9-]+\:\/+)([^\/\s]+)([a-z0-9\-@\^=%&;\/~\+]*)[\?]?([^ \#\r\n]*)#?([^ \#\r\n]*)/mig;
var str = 'Bob: Hey there, have you checked https://www.facebook.com ?\n(ignore) https://github.com/justsml?tab=activity#top (ignore this too)';
var m;

while ((m = re.exec(str)) !== null) {
    if (m.index === re.lastIndex) {
        re.lastIndex++;
    }
    console.log(m);
}

Will give you the following:

["https://www.facebook.com",
  "https://",
  "www.facebook.com",
  "",
  "",
  ""
]

["https://github.com/justsml?tab=activity#top",
  "https://",
  "github.com",
  "/justsml",
  "tab=activity",
  "top"
]

Answer 3

You have to escape the backslash when you are using new RegExp .

Also you can put the dash - at the end of character class to avoid escaping it.

& inside a character class means & or a or m or p or ; , you just need to put & and ; , a, m and p are already match by \\w .

So, your regex becomes:

var urlexp = new RegExp( '(http|ftp|https)://[\\w-]+(\\.[\\w-]+)+([\\w-.,@?^=%&:/~+#-]*[\\w@?^=%&;/~+#-])?' );

Answer 4

为许多 URL 格式尝试这个通用正则表达式

/(([A-Za-z]{3,9})://)?([-;:&=\+\$,\w]+@{1})?(([-A-Za-z0-9]+\.)+[A-Za-z]{2,3})(:\d+)?((/[-\+~%/\.\w]+)?/?([&?][-\+=&;%@\.\w]+)?(#[\w]+)?)?/g

Answer 5

试试(http|ftp|https):\\/\\/[\\w\\-_]+(\\.[\\w\\-_]+)+([\\w\\-\\.,@?^=%&:/~\\+#]*[\\w\\-\\@?^=%&/~\\+#])?

Answer 6

I've cleaned up your regex:

var urlexp = new RegExp('(http|ftp|https)://[a-z0-9\-_]+(\.[a-z0-9\-_]+)+([a-z0-9\-\.,@\?^=%&;:/~\+#]*[a-z0-9\-@\?^=%&;/~\+#])?', 'i');

Tested and works just fine ;)

Answer 7

try this worked for me

/^((ftp|http[s]?):\/\/)?(www\.)([a-z0-9]+)\.[a-z]{2,5}(\.[a-z]{2})?$/

that is so simple and understandable

Answer 8

The trouble is that the "-" in the character class (the brackets) is being parsed as a range: [az] means "any character between a and z." As Vini-T suggested, you need to escape the "-" characters in the character classes, using a backslash.