如何在Linux的Java程序中打开包含GUI的.bat？

Question

everyone. I'm quite new here so please be tolerant if I make any mistakes.

I have a .bat file containing a command line to open up a .jar file that contains a program that has a GUI in it. The only line that's in the .bat file is:

    java -jar "NewServer.jar" 

I've been trying to use Runtime() to get this to run, but most the instructions I find to open a .bat file in a java program are for Windows. I'm currently using Fedora 12 (don't tell me to upgrade, I can't) if that makes a difference and programming using Eclipse. I also found this ProcessBuilder thing, but I couldn't get it to work so unless you have very explicit directions on how to use it, please don't include it in your answer. I would much rather use Runtime. It looked simpler.

Here's my code to test using Runtime in a java program. I'm hoping that if I can get this to work, I can get it to work in my real program.

import java.io.IOException;

public class testbat {

  public static void main(String[] args) {

    Process proc = null;
    try {
        proc = Runtime.getRuntime().exec("./ myServer.bat");
    } catch (IOException e) {

        e.printStackTrace();
    }

      System.out.println("Cool");


}

The last line is just there for me to see if the program actually ran in case the GUI doesn't open. Also, I've already tried many combinations of things to include in the area after ".exec". I've tried using a path like "~/user/workspace/ProjectServer/dist/myServer.bat" to no avail.

I also already know that .bat files are for windows, but I'm able to execute it in linux, so I don't know if that makes a difference. I also tried using a .sh file the same way and it didn't work.

Please bear in mind that I'm not that great at Java, but I had to use it for this particular program, so if your answers could be really descriptive that would be awesome.

Answer 1

Just take that line out of the bat file, and run it. Yo're making it too hard.

$ java -jar "NewServer.jar"

will work. The quotes aren't necessary, so

$ java -jar NewServer.jar

will work as well. If you want to have the equivalent of your bat file, create a file named, say, run_newserver containing that line. Change its mode to executable:

$ cat > run_newserver
java -jar NewServer.jar
^D
$ chmod a+x run_newserver
$ ./run_newserver

Ideally, since you shouldn't have scripts without comments, do this. In your favorite editor, create a file run_newserver containing

#!/usr/bin/env bash
java -jar NewServer.jar

and chmod that. The line with #! -- often called a "shebang line" -- is UNIX magic that lets you say what interpreter you want. The program env in usr/bin finds your program and runs it (needed because different systems put bash in different directories.)

You could even put explanatory comments in the file too.

I'm a little unclear why you want to use Runtime#exec to run it at all -- it seems you'll just need a shell script to start that program.

Answer 2

Why are you using Java to run a Batch file, that in turn runs a Java program? Why have Batch in the loop at all? Just put the jar in your classpath and call it directly.

Answer 3

Batch (.bat) files are only for Windows environment. So, Try using shell script

 Process proc = Runtime.getRuntime().exec("myServer.sh");

Answer 4

Just open up terminal and do this

vi /dir/to/exec/exec.sh

tap "i" and write this

#!/bin/sh
java -jar "NewServer.jar"

or if you want to run it in the background

#!/bin/sh
java -jar "NewServer.jar" & > /tmp/JavaServer.log

hit esc and type ":wq" and you have saved the file.

type this into the terminal

chmod +x /dir/to/exec/exec.sh

this give executable privileges and then you should run the file like

sh /dir/to/exec/exec.sh

Answer 5

Process is only initialized by your first call. You need to run:

proc.waitfor();

to get it to actually run your app.