如何仅获取特定文件的父目录名称

Question

如何从 test.java 所在的路径名中获取ddd 。

File file = new File("C:/aaa/bbb/ccc/ddd/test.java");

Answer 1

Use File 's getParentFile() method and String.lastIndexOf() to retrieve just the immediate parent directory.

Mark's comment is a better solution than lastIndexOf() :

file.getParentFile().getName();

These solutions only works if the file has a parent file (eg, created via one of the file constructors taking a parent File ). When getParentFile() is null you'll need to resort to using lastIndexOf , or use something like Apache Commons' FileNameUtils.getFullPath() :

FilenameUtils.getFullPathNoEndSeparator(file.getAbsolutePath());
=> C:/aaa/bbb/ccc/ddd

There are several variants to retain/drop the prefix and trailing separator. You can either use the same FilenameUtils class to grab the name from the result, use lastIndexOf , etc.

Answer 2

File f = new File("C:/aaa/bbb/ccc/ddd/test.java");
System.out.println(f.getParentFile().getName())

f.getParentFile() can be null, so you should check it.

Answer 3

Since Java 7 you have the new Paths api . The modern and cleanest solution is:

Paths.get("C:/aaa/bbb/ccc/ddd/test.java").getParent().getFileName();

Result would be:

C:/aaa/bbb/ccc/ddd

Answer 4

Use below,

File file = new File("file/path");
String parentPath = file.getAbsoluteFile().getParent();

Answer 5

If you have just String path and don't want to create new File object you can use something like:

public static String getParentDirPath(String fileOrDirPath) {
    boolean endsWithSlash = fileOrDirPath.endsWith(File.separator);
    return fileOrDirPath.substring(0, fileOrDirPath.lastIndexOf(File.separatorChar, 
            endsWithSlash ? fileOrDirPath.length() - 2 : fileOrDirPath.length() - 1));
}

Answer 6

File file = new File("C:/aaa/bbb/ccc/ddd/test.java");
File curentPath = new File(file.getParent());
//get current path "C:/aaa/bbb/ccc/ddd/"
String currentFolder= currentPath.getName().toString();
//get name of file to string "ddd"

if you need to append folder "ddd" by another path use;

String currentFolder= "/" + currentPath.getName().toString();

Answer 7

From java 7 I would prefer to use Path. You only need to put path into:

Path dddDirectoryPath = Paths.get("C:/aaa/bbb/ccc/ddd/test.java");

and create some get method:

public String getLastDirectoryName(Path directoryPath) {
   int nameCount = directoryPath.getNameCount();
   return directoryPath.getName(nameCount - 1);
}

Answer 8

In Groovy:

There is no need to create a File instance to parse the string in groovy. It can be done as follows:

String path = "C:/aaa/bbb/ccc/ddd/test.java"
path.split('/')[-2]  // this will return ddd

The split will create the array [C:, aaa, bbb, ccc, ddd, test.java] and index -2 will point to entry before the last one, which in this case is ddd

Answer 9

    //get the parentfolder name
    File file = new File( System.getProperty("user.dir") + "/.");
    String parentPath = file.getParentFile().getName();

Answer 10

For Kotlin :

 fun getFolderName() {
            
            val uri: Uri
            val cursor: Cursor?
    
            uri = MediaStore.Audio.Media.EXTERNAL_CONTENT_URI
            val projection = arrayOf(MediaStore.Audio.AudioColumns.DATA)
            cursor = requireActivity().contentResolver.query(uri, projection, null, null, null)
            if (cursor != null) {
                column_index_data = cursor.getColumnIndexOrThrow(MediaStore.Audio.AudioColumns.DATA)
            }
            
            while (cursor!!.moveToNext()) {
    
                absolutePathOfImage = cursor.getString(column_index_data)
    
    
                val fileName: String = File(absolutePathOfImage).parentFile.name
    }
}