[英]Why doesn't using nonlocal scope variable as default value for parameter work?
Code would explain this much better :) 代码会更好地解释:)
def a():
x=0
def b(z=x):
print("X: %d, Z: %d" % (x,z,))
x=5
b()
Result: 结果:
X: 5, Z: 0
What's going on here? 这里发生了什么?
(Ok, now I've figured it out) (好吧,现在我已经弄明白了)
Ok, the answer from the Python docs is: 好的,Python文档的答案是:
Default parameter values are evaluated when the function definition is executed.
执行函数定义时,将评估默认参数值。 This means that the expression is evaluated once, when the function is defined, and that the same “pre-computed” value is used for each call.
这意味着当定义函数时,表达式被计算一次,并且每次调用使用相同的“预先计算”值。
Fair enough. 很公平。
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