[英]Get input in shell script
I know to get an input with a shell script you can do 我知道要输入可以执行的shell脚本
echo "text"
read $VAR
or to get it at runtime 或在运行时获取
#! /bin/sh
if [ "$1" ]
then
#do stuff
else
echo "No input"
fi
But what if I want to get the entire string after I run it, including spaces? 但是,如果我想在运行后获取整个字符串(包括空格)怎么办? I could use quotation marks, but is there any way around this, so I can do:
./script.sh This is a sentence
我可以使用引号,但是有什么办法可以解决,所以我可以这样做:
./script.sh This is a sentence
Use 采用
#!/bin/sh
if [ $# -gt 0 ] ; then
echo "$*"
else
echo "No input"
fi
But first, think about what you're doing and just pass a single quoted parameter. 但是首先,请考虑您在做什么,只传递一个引用的参数即可。
./script.sh "This is a sentence"
另一种方法是
./script.sh This\ is\ a\ sentence
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