需要PHP正则表达式来从主题行解析Twitter名称

Question

I'm using PHP and trying to parse this subject line to isolate just the twitter name (@MargyM):

Margaret M (@MargyM) is now following you on Twitter

Note that the user name (before the twitter name) can be something else, with parens, so the regex needs to be smart enough to work around that-- ie any of these could be valid inputs:

Margaret M (:) (@MargyM) is now following you on Twitter
Margaret M ):) (@MargyM) is now following you on Twitter
Margaret M. :) (@MargyM) is now following you on Twitter
Margaret M (-- (@MargyM) is now following you on Twitter
Margaret M ( : (@MargyM) is now following you on Twitter
Margaret M (_: (@MargyM) is now following you on Twitter

So to be clear, the RegEx should look at the bit of text between the final set of parens before "is now following you..." to get the Twitter name.

EDIT: it's also possible that one or more "@" signs could appear before the twitter name, ie anything like this:

Margaret @ Minnesota (@MargyM) is now following you on Twitter
Margaret @ Minnesota :-) (@MargyM) is now following you on Twitter
Margaret @ Minnesota (-) (@MargyM) is now following you on Twitter
Margaret @ Minnesota (tweet @ME!) (@MargyM) is now following you on Twitter
etc.

Answer 1

This?

if (preg_match('/(?<=@).*(?=\))/', $subject, $regs)) {
    #$regs[0];
}

After your edit :

if (preg_match('/(?<=@)(?!.*@).*(?=\))/', $subject, $regs)) {
    #$regs[0];
}

Explanation:

"
(?<=     # Assert that the regex below can be matched, with the match ending at this position (positive lookbehind)
   @        # Match the character “@” literally
)
(?!      # Assert that it is impossible to match the regex below starting at this position (negative lookahead)
   .        # Match any single character that is not a line break character
      *        # Between zero and unlimited times, as many times as possible, giving back as needed (greedy)
   @        # Match the character “@” literally
)
.        # Match any single character that is not a line break character
   *        # Between zero and unlimited times, as many times as possible, giving back as needed (greedy)
(?=      # Assert that the regex below can be matched, starting at this position (positive lookahead)
   \)       # Match the character “)” literally
)
"

Answer 2

$regex = "/(\(@.+\))/i";
preg_match( $regex , $input , $match );

Answer 3

A very simple solution:

/\((@[^)]+)\) is now following you on Twitter/

Or alternatively, if the following text isn't always like that but never contains any @ itself:

/\((@[^)]+)\)(?:[^@]+)$/m

You can see a working example of the first here and of the second here .