[英]Extract dollar amount from string - regex in PHP
i am hvaing a challenge trying to do this reliably for all possible strings. 我正在尝试为所有可能的字符串可靠地执行此操作。
Here are the possible values of $str: 以下是$ str的可能值:
There is a new $66 price target 价格目标是新的66美元
There is a new $105.20 price target 价格目标为105.20美元
There is a new $25.20 price target 价格目标是新的25.20美元
I want a new $dollar_amount to extract just the dollar amount from the above sample strings. 我想要一个新的$ dollar_amount来从上面的示例字符串中提取美元金额。 eg $dollar_amount = 66/105.20/25.20 in above cases. 例如,在上述情况下,$ dollar_amount = 66 / 105.20 / 25.20。 How can i reliably do this with a regex statement in PHP? 我如何使用PHP中的正则表达式可靠地执行此操作? Thanks 谢谢
preg_match('/\$([0-9]+[\.,0-9]*)/', $str, $match);
$dollar_amount = $match[1];
will be probably the most suitable one 可能是最合适的一个
Try this: 试试这个:
if (preg_match('/(?<=\$)\d+(\.\d+)?\b/', $subject, $regs)) {
#$result = $regs[0];
}
Explanation: 说明:
"
(?<= # Assert that the regex below can be matched, with the match ending at this position (positive lookbehind)
\$ # Match the character “\$” literally
)
\d # Match a single digit 0..9
+ # Between one and unlimited times, as many times as possible, giving back as needed (greedy)
( # Match the regular expression below and capture its match into backreference number 1
\. # Match the character “.” literally
\d # Match a single digit 0..9
+ # Between one and unlimited times, as many times as possible, giving back as needed (greedy)
)? # Between zero and one times, as many times as possible, giving back as needed (greedy)
\b # Assert position at a word boundary
"
You need this regular expression: 你需要这个正则表达式:
/(\$([0-9\.]+))/
What is the function that meet your needs is up to you. 满足您需求的功能取决于您。
You can find then regex functions for PHP here: http://www.php.net/manual/en/ref.pcre.php 你可以在这里找到PHP的正则表达式函数: http : //www.php.net/manual/en/ref.pcre.php
尝试
#.+\$(.+)\s.+#
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