如何将参数传递给fileURL

Question

I'm trying to pass arguments in NSURL of file path in the usual way:

(fileURL)?arg1=val1&arg2=val2

The problem is that I keep getting the following error from the UIWebView :

Failed to load webpage with error: The requested URL was not found on this server.

When I remove the arguments suffix everything works perfect. The documentation on Apple state that the method

+ (id)fileURLWithPath:(NSString *)path

Works like this: "path: The path that the NSURL object will represent. path should be a valid system path..."

Is it possible to add the arguments to fileURL? If so, how can I do it?

By the way, I succeeded to do so, if I try to load local URL file with arguments from the UIWebView with Javascript call:

document.location = url;

I try to find the solution from native code...

Answer 1

Ok, I see your problem. You can't add the ?arg1=something&arg2=... to the path, because there could be a file named like that, so NSURL escapes the ? character to ensure it's used as a path, not part of the query string (anything after the ? is called a query in a URL).

To do this properly, you need to set the URL by giving a properly escaped string.

NSString *path = @"/Users/mike/file.html"; 
NSString *query = @"option1=5&option2=hello"; // for example

NSString *encodedPath = [path stringByAddingPercentEscapesUsingEncoding: NSUTF8StringEncoding];
NSURL *url = [NSURL URLWithString:[NSString stringWithFormat:@"file://%@?%@",
                                   encodedPath,
                                   query]];

Answer 2

Have you tried using the fragment instead? It's the part of the URL after the # symbol. This part is never sent to the server, so shouldn't interfere with the path, but javascript on the page can still read it.