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使用-O3的osx上的g ++优化错误

[英]g++ optimization bug on osx using -O3

The following code produces the wrong exit code when compiled with -O3. 使用-O3编译时,以下代码将产生错误的退出代码。 I think the inner loop is being optimized away incorrectly. 我认为内循环被错误地优化了。 With -O2 or -fno-inline it works. 使用-O2或-fno-inline可以正常工作。 Producing a simpler example is difficult because any small changes and the bug disappears. 产生一个简单的示例很困难,因为任何小的更改都会使错误消失。

Compiled with: 编译:

/usr/bin/g++ -O3 -o bugexample bugexample.cpp

Code: 码:

#include <vector>

int test(std::vector<char>& a, int& b)
{
    std::vector<int> z;
    z.push_back(10);
    z.push_back(10);

    int d = (int)a.size();

    int x = 1;
    for (int j = 0; j < 2; j++)
    {
        int c = j - 1;

        for (int i = 0; i < d; i++) 
        {
            if (j == 0)
            {
            }
            else if (i == 0)
            {
            }
            else
            {
                if (a[j] == a[i - 1])
                {
                    b = c + 1;
                    x = 2;
                }
                z[i] = 1;
            }
        }
    }

    return x;
}


int main(int argc, char* argv[])
{
    std::vector<char> a;
    a.push_back('a');
    a.push_back('a');
    int b = 1;
    return test(a,b);
}

Compiler version: 编译器版本:

/usr/bin/g++ -v
Using built-in specs.
Target: i686-apple-darwin10
Configured with: /var/tmp/gcc/gcc-5666.3~123/src/configure --disable-checking --enable-werror --prefix=/usr --mandir=/share/man --enable-languages=c,objc,c++,obj-c++ --program-transform-name=/^[cg][^.-]*$/s/$/-4.2/ --with-slibdir=/usr/lib --build=i686-apple-darwin10 --program-prefix=i686-apple-darwin10- --host=x86_64-apple-darwin10 --target=i686-apple-darwin10 --with-gxx-include-dir=/include/c++/4.2.1
Thread model: posix
gcc version 4.2.1 (Apple Inc. build 5666) (dot 3)

Interested in any insite, or proof that its my fault. 对任何现场感兴趣,或证明它是我的错。

Edit: The exit code produced is 1, whereas it should b 2. 编辑:产生的退出代码为1,而应为b 2。

Mmm is this some kind of obfuscated code contest? 嗯,这是某种混淆代码竞赛吗?

As far as I can tell you're trying to do some kind of palindrome test on the input vector. 据我所知,您正在尝试对输入向量进行某种回文检验。 Only, 只要,

  • the loop var j has a hardcoded upperbound of 2 (which should probably have been a.size() as well?) 循环var j的硬编码上限为2 (应该也应该是a.size()?)
  • you only return the check of the last position 您只返回最后一个位置的支票
  • you had all kinds of redundant conditions 你有各种各样的冗余条件
  • you had gratuitous non-const arguments 你有不必要的非常量参数
  • you had unused z vector 您有未使用的z向量
  • you had unnecessary use of int for bool (1=>false - not found, 2=>true - found) 您对bool不必要地使用了int(1 => false-找不到,2 => true-找到)
  • you had unnecessary use of out parameter b ; 您没有必要使用out参数b I replaced that bool return type with the value of b (with b==-1 indicating no match found) 我用b的值替换了bool返回类型(b ==-1表示找不到匹配项)

When simplifying the code for these things, I get this code, and (like your own code) it behaves identically for all optimization levels on g++ 4.6.1: 在简化这些代码时,我得到了这段代码,并且(就像您自己的代码一样),对于g ++ 4.6.1上的所有优化级别,其行为都相同:

#include <vector>

int test(const std::vector<char>& a)
{
    /* int j = 1; // was: for (int j = 1; j < 2; j++) */

    for (int i = a.size()-1; i > 1; i--) 
        if (a[1] == a[i - 1])
            return 1;

    return -1;
}


int main(int argc, char* argv[])
{
    std::vector<char> a(2, 'a');
    int b = test(a);

    return b==-1? 1 : 2;
}

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