使用XPath解析XML文档

Question

Lets say I have the following xml (a quick example)

<rows>
   <row>
      <name>one</name>
   </row>
   <row>
      <name>two</name>
   </row>
</rows>

I am trying to parse this by using XmlDocument and XPath (ultimately so I can make a list of rows).

For example...

XmlDocument doc = new XmlDocument();
doc.LoadXml(xml);

foreach(XmlNode row in doc.SelectNodes("//row"))
{
   string rowName = row.SelectSingleNode("//name").InnerText;
}

Why, within my foreach loop, is rowName always "one"? I am expecting it to be "one" on the first iteration and "two" on the second.

It seems that //name gets the first instance in the document, rather than the first instance in the row as I would expect. After all, I am calling the method on the "row" node. If this is "just how it works" then can anybody please explain how I could change it to work to my needs?

Thank you

Answer 1

XmlDocument doc = new XmlDocument();
doc.LoadXml(xml);

foreach(XmlNode row in doc.SelectNodes("//row"))
{
   var rowName = row.SelectSingleNode("name");
}

Is the code you posted actually correct? I get a compile error on row.SelectNode() as it isn't a member of XmlNode.

Anyway, my example above works, but assumes only a single <name> node within the <row> node so you may need to use SelectNodes() instead of SelectSingleNode() if that is not the case.

As others have shown, use .InnerText to get just the value.

Answer 2

Use LINQ to XML. Include using System.Xml.Linq; in your code file and then do the following code to get your list

XDocument xDoc = XDocument.Load(filepath);
IEnumerable<XElement> xNames;

xNames = xDoc.Descendants("name");

That will give you a list of the name elements. Then if you want to turn that into a List<string> just do this:

List<string> list = new List<string>();
foreach (XElement element in xNames)
{
    list.Add(element.value);
}

Answer 3

Your second xpath starts with // . This is an abbreviation for /descendant-or-self::node() , which you can see starts with / , meaning it searches from the root of the document , whatever the context in which you use it.

You probably want one of:

var rowName = row.SelectSingleNode("name");

to find the name nodes that are immediate children of the row , or

var rowName = row.SelectSingleNode(".//name");

to find name nodes *anywhere under the row . Note the . Note the .` in this second xpath that causes the xpath to start from the context node.

Answer 4

Use a relative path eg string rowName = row.SelectSingleNode("name").InnerText; .

Answer 5

The problem is in your second XPath query:

//row

This has a global scope, so no matter where you call it from, it will select all row elements.

It should work if you replace your expression with:

.//row

Answer 6

我会使用SelectSingleNode，然后使用InnerText属性。

var rowName = row.SelectSingleNode("name").InnerText;

Answer 7

Use the following

        doc.LoadXml(xml);

            foreach(XmlNode row in doc.SelectNodes("/rows/row"))
            {
                string rowName = row.SelectSingleNode("//name").InnerText.ToString();
            }