将当前日期增加5天

Question

$date = date('Y-m-d',current_time('timestamp', 0));

How do I change $date to $date + 5 days ?

PHP version is 5.2.

This code doesn't work:

$date_cur = date('Y-m-d',current_time('timestamp', 0));
echo $date_cur . ' <br>';
$date_cur_plus = date($date_cur, strtotime('+5 days'));
echo $date_cur_plus;

Gives me:

2011-11-29 
2011-11-29

Answer 1

$date = date('Y-m-d', strtotime('+5 days'));

Answer 2

You could use mktime() using the timestamp.

Something like:

$date = date('Y-m-d', mktime(0, 0, 0, date('m'), date('d') + 5, date('Y')));

Using strtotime() is faster, but my method still works and is flexible in the event that you need to make lots of modifications. Plus, strtotime() can't handle ambiguous dates.

Edit

If you have to add 5 days to an already existing date string in the format YYYY-MM-DD , then you could split it into an array and use those parts with mktime() .

$parts = explode('-', $date);
$datePlusFive = date(
    'Y-m-d', 
    mktime(0, 0, 0, $parts[1], $parts[2] + 5, $parts[0])
    //              ^ Month    ^ Day + 5      ^ Year
);

Answer 3

Object oriented Style:

<?php
    $date = new DateTime('now');
    $date->add(new DateInterval('P5D'));
    echo $date->format('Y-m-d') . "\n";
?>

Procedural Style:

<?php
    $date = date_create('2016-01-01');
    date_add($date, date_interval_create_from_date_string('5 days'));
    echo date_format($date, 'Y-m-d');
?>

Answer 4

strtotime() is very nice. It allows you to do the following:

$startDate = 'now'; // or choose a certain date you want/have
$startDate = '2013-02-14';
$intervals = array(
    '', 
    '+ 5 days', 
    '+ 31 days', 
    '+ 3 months', 
    '+ 2 years + 2 days'
); 
foreach($intervals as $interval) {
    $combinedDate = $startDate . ' ' . $interval;
    var_dump($combinedDate . ' => ' date('Y-m-d', strtotime($combinedDate)));
}

with a result:

now => 1360334498 = 2013-02-08

now + 5 days => 1360766498 = 2013-02-13

now + 31 days => 1363012898 = 2013-03-11

now + 3 months => 1368020498 = 2013-05-08

now + 2 years + 2 days => 1423579298 = 2015-02-10

or:

2013-02-14 => 1360792800 = 2013-02-14

2013-02-14 + 5 days => 1361224800 = 2013-02-19

2013-02-14 + 31 days => 1363471200 = 2013-03-17

2013-02-14 + 3 months => 1368478800 = 2013-05-14

2013-02-14 + 2 years + 2 days => 1424037600 = 2015-02-16

Answer 5

For specific date:

$date = '2011-11-01';
$date_plus = date('Y-m-d', strtotime($date.'+5 days'));
echo $date.'<br>'.$date_plus;

It will be give :

2011-11-01
2011-11-06

Answer 6

使用strtotime ：

$date = date('Y-m-d', strtotime('+5 days'));

Answer 7

$dateplus5 = date('Y-m-d', strtotime('+5 days'));

Answer 8

You can use

strtotime(“+5 days”)

to get the current date plus 5 days or

$targetDate = date($date, strtotime(’+5 days’));

Answer 9

I used this:

$date = strtotime("+1 day", strtotime("2007-02-28"));
echo date("Y-m-d", $date);

It's working now.

Answer 10

Did not supposed to be like this?

$date_cur = date('Y-m-d', current_time('timestamp', 0));
echo $date_cur . ' <br>';
$date_cur_plus = date('Y-m-d', strtotime('+5 days', current_time('timestamp', 0) ) );
echo $date_cur_plus;

Answer 11

如果日期已经存在，则可以使用以下代码：

$tartDate = date("m/d/Y", strtotime("+1 Day", strtotime($Date)));