如何在匹配/匹配后使用“sed”删除2行？

Question

I have the following command : sed -i -e '/match1/,+2d' filex , which deletes 2 lines after finding the match "match1" in the file "file x". I want to add several matches to it, like match1, match 2 ....

So it will delete 2 lines after finding any of the matches, how can I achieve this ?

Answer 1

Two ways, depending upon the sed version and platform:

sed -e '/match1/,+2d' -e '/match2/,+2d' < oldfile > newfile

or

sed -e '/match1\|match2/,+2d' < oldfile > newfile

Answer 2

Not a sed user but it seems to me you could use :

sed -i -e '/(match1|match2)/,+2d' filex

Otherwise you could, if that's possible for you to do, do :

sed -i -e '/match1/,+2d' filex && sed -i -e '/match2/,+2d' filex

EDIT: Looks like I had the right idea but ziu got it.

Answer 3

If I understand you correctly, you want

sed -e '/match1/,+2d' input.txt

For example, create input with seq 10 | sed '3i match1' > input.txt seq 10 | sed '3i match1' > input.txt :

1
2
match1
3
4
5
6
7
8
9
10

The output of sed -e '/match1/,+2d' input.txt would be:

1
2
5
6
7
8
9
10