[英]Java: Get URI from FilePath
I've little knowledge of Java. 我对Java知之甚少。 I need to construct a string representation of an URI from
FilePath(String)
on windows. 我需要在Windows上从
FilePath(String)
构造一个URI的字符串表示。 Sometimes the inputFilePath
I get is: file:/C:/a.txt
and sometimes it is: C:/a.txt
. 有时我得到的
inputFilePath
是: file:/C:/a.txt
,有时它是: C:/a.txt
。 Right now, what I'm doing is: 现在,我正在做的是:
new File(inputFilePath).toURI().toURL().toExternalForm()
The above works fine for paths, which are not prefixed with file:/
, but for paths prefixed with file:/
, the . 上面的方法适用于路径,它不带有
file:/
前缀,但对于带有file:/
前缀的路径file:/
,。 toURI
method is converting it to a invalid URI, by appending value of current dir, and hence the path becomes invalid. toURI
方法通过附加当前dir的值将其转换为无效的URI,因此路径变为无效。
Please help me out by suggesting a correct way to get the proper URI for both kind of paths. 请通过建议正确的方法为这两种路径获取正确的URI来帮助我。
These are the valid file uri: 这些是有效的文件uri:
file:/C:/a.txt <- On Windows
file:///C:/a.txt <- On Windows
file:///home/user/a.txt <- On Linux
So you will need to remove file:/
or file:///
for Windows and file://
for Linux. 因此,您需要删除
file:/
或file:///
for Windows和file://
for Linux。
From SAXLocalNameCount.java from https://jaxp.java.net : 来自https://jaxp.java.net的 SAXLocalNameCount.java:
/**
* Convert from a filename to a file URL.
*/
private static String convertToFileURL ( String filename )
{
// On JDK 1.2 and later, simplify this to:
// "path = file.toURL().toString()".
String path = new File ( filename ).getAbsolutePath ();
if ( File.separatorChar != '/' )
{
path = path.replace ( File.separatorChar, '/' );
}
if ( !path.startsWith ( "/" ) )
{
path = "/" + path;
}
String retVal = "file:" + path;
return retVal;
}
Just use Normalize();
只需使用
Normalize();
Example: 例:
path = Paths.get("/", input).normalize();
this one line will normalize all your paths. 这一行将规范你的所有路径。
The argument to new File(String)
is a path, not a URI. new File(String)
的参数是路径,而不是URI。 The part of your post after 'but' is therefore an invalid use of the API. 因此,“但是”之后的帖子部分是对API的无效使用。
class TestPath {
public static void main(String[] args) {
String brokenPath = "file:/C:/a.txt";
System.out.println(brokenPath);
if (brokenPath.startsWith("file:/")) {
brokenPath = brokenPath.substring(6,brokenPath.length());
}
System.out.println(brokenPath);
}
}
Gives output: 给出输出:
file:/C:/a.txt
C:/a.txt
Press any key to continue . . .
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