c＃实现接口的类中的虚方法

Question

Lets say I have the following class:

namespace myNamespace
{
    [TypeLibType((short)2)]
    [ClassInterface((short)0)]
    [ComImport]
    public class myClass : myInterface
    {
        public virtual void myMethod();
    }
}

and lets say I have the following interface which that class implements

namespace myNamespace
{
    [Guid("2105896C-2B38-4031-BD0B-7A9C4A39FB93")]
    [TypeLibType((short)4160)]
    [ComImport]
    public interface myInterface
    {
        void myMethod();
    }
}

Now, when I compile this the virtual method in the first class comes back with the following error:

'myNamespace.myClass.myMethod()' must declare a body because it is not marked abstract, extern, or partial

This method should compile just fine because it is marked as virtual, but for some reason it still will not compile and I'm kind of at a loss as to why because if I alternatively define a body on MyMethod in MyClass then I get the following error instead:

Since 'myClass.myMethod' has the ComImport attribute, 'myNamespace.myClass.myMethod' must be extern or abstract

I'm using .Net 3.5 for this setup, but it still doesn't work in .Net 4.0 either

Answer 1

I think you are confusing virtual with abstract . Virtual methods require an implemenation, but may be overridden.

Abstract methods on the other hand can be declared as you have it without an implementation. Subclasses then bear the responsibility of providing the implementation, and if they don't they are greeted with a compiler error.