[英]Sequelize how to find rows with multiple where clauses and timestamp > NOW()
How do I do this with Sequelize? 我如何用Sequelize做到这一点?
SELECT FROM sessions WHERE user_id = ? AND token = ? AND expires > NOW()
Here's what I'm trying to do (assume Session
is a Sequelize model): 这是我正在尝试做的事情(假设
Session
是Sequelize模型):
Session.find({
where: {
user_id: someNumber,
token: someString,
//expires > NOW() (how do I do this?)
}
}).on('success', function (s) { /* things and stuff */ });
Thanks! 谢谢!
did you try to use the array notation of finders in sequelize? 你试图在sequelize中使用finders的数组符号吗?
Session.find({
where: ['user_id=? and token=? and expires > NOW()', someNumber, someString]
}).on('success', function (s) { /* things and stuff */ });
You can checkout this page: http://sequelizejs.com/?active=find-objects#find-objects 您可以查看此页面: http : //sequelizejs.com/? active = find-objects#find- objects
Hope this works. 希望这有效。 Otherwise it's a bug :D
否则这是一个错误:D
Please note that as of this posting and the most recent version of sequelize, the above answers are out of date. 请注意,截至本帖子和最新版本的续集,上述答案已过时。 I am posting the solution that I got working in hopes of saving someone some time.
我发布了我工作的解决方案,希望能节省一些时间。
filters["State"] = {$and: [filters["State"], {$not: this.filterSBM()}] };
Note the $ and array inside the JSON object and lack of ? 注意JSON对象里面的$和数组缺少? token replacement.
令牌替换。
Or put in a more general way, since that might help someone wrap their head around it: 或者以更一般的方式,因为这可能有助于有人围绕它:
{ $and: [{"Key1": "Value1"}, {"Key2": "Value2"}] }
Another method: 另一种方法:
Session.find({
where: {
user_id: someNumber,
token: someString,
expires: {
$gt: (new Date())
}
}
}).on('success', function (s) { /* things and stuff */ });
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