将数据库结果的条件指定给数组

Question

In my database I have a field called "modules" - info data looks like this: 1, 4, 1, 3 I want to list/output all data via PHP with the numbers 1 - all other numbers have to be ignored.

I want to check the output result via an array NOT via mySQL

Any suggestion how I can do that?

$list_modules = array();
            $res_m = $db->Execute("SELECT modules FROM users u WHERE user_id = '".$user->id."'");
            while ( $m = $res_m->GetNext() ) {
                $list_modules = array($m['modules']);
            }

            print_r($list_modules); //Output below 

Example (Output):

Array
(
    [0] => 1, 4, 1, 3
)

Answer 1

You can do that in you MySQL with a WHERE clause. Depending on the column name in the database:

SELECT column_name FROM table WHERE column_name = 1;

Note: In your question it looks like you tried to list a range:

with the numbers 1 - all other numbers have to be ignored.

If you meant to put a range (eg 1 - 4) then your WHERE clause would be:

WHERE column_name BETWEEN 1 AND 4

Answer 2

You should test for that in your MySQL query:

SELECT * FROM `TABLE` WHERE `modules` = 1;

Or, alternatively, if that's not possible..

Loop with foreach and test for 1?

$array = array(1,4,1,3);
foreach ($array as $element) {
    if ($element == 1) { echo 1; }
}

Answer 3

You stated in your comment that the modules field contains comma-separated values, is that right? I reckon that the modules field is VARCHAR , CHAR , or any other string. If so, you could use a query like:

SELECT * FROM `tableName` WHERE `modules` LIKE '%1,%';

There may be other solutions, probably more optimal, but this one should perform well, I think.

Answer 4

This should do it... there is really no other way seeing at the col is Varchar, you also need to eliminate strings like 15, 21, etc. so %1% will not work.

SELECT modules FROM users WHERE user_id = ".$user->id." AND modules LIKE % 1,%

Give it a shot and let me know if it works.

Answer 5

Meh found the solution I could use.

$list_modules = array();
            $query = "SELECT modules FROM users WHERE user_id = ".$user->id."";
            $res_m = $db->Execute($query);
            while ( $m = $res_m->GetNext() ) {
                $list_modules = array('id' => $m['modules']);
            }

$modules = explode(",",$list_modules['id']);
            foreach ($modules as $key => $value) {

                if($value == 1){
                // list data    
                   }
                }
            }