将cURL命令转换为Python的urllib2

Question

guys! I'm currently working with an API that uses the following cURL line:

curl -vF "files[]=@file.zip" "http://s5.example.com/123"

I'm not interested in using other libraries such as pycurl, because I really only need to convert a line or two. I really appreciate your help!

Answer 1

This request posts the file contents in a file upload field. The http body of a POST request uploading a file is tricky to assemble - for ordinary text fields, one can just send a dictionary in the "data=" parameter to a urllib2.urlopen call, and the fields will be posted.

File uploads, though, need to send a complex http body, with customized headers. I don't know if urllib2 can do this - but I found an example on how to do it using httplib and mimetypes (both part of Python's stdlib) - so you can pick the example code and reuse it on your project:

http://code.activestate.com/recipes/146306-http-client-to-post-using-multipartform-data/

Answer 2

All you need is urlopen method of urllib module .. .

Syntax: urllib2.urlopen(url[, data][, timeout])

data is the string specifying additional stuff to send to the server

Example:

import urllib
tlds = urllib.urlopen("http://data.iana.org/TLD/tlds-alpha-by-domain.txt").readlines()

this example shows a single line code to extract all tlds into aa list called tlds by crawling it from iana.org

For complex operations/options/parameters of urlopen method you can check the official documentation: http://docs.python.org/library/urllib2.html