为数组中的所有元素分配相同值的方法

Question

Is there anyway to do this? This is my first time using an array and its 50 elements and i know they will only get bigger.

Answer 1

Whatever kind of array you are using, if it provides iterators/pointers you can use the std::fill algorithm from the <algorithm> header.

// STL-like container:
std::fill(vect.begin(), vect.end(), value);

// C-style array:
std::fill(arr, arr+elementsCount, value);

(where value is the value you want to assign and elementsCount is the number of elements to modify)

Not that implementing such a loop by hand would be so difficult...

// Works for indexable containers
for(size_t i = 0; i<elementsCount; ++i)
    arr[i]=value;

Answer 2

使用std::vector ：

std::vector<int> vect(1000, 3); // initialize with 1000 elements set to the value 3.

Answer 3

You can use a for loop if you must use arrays:

int array[50];

for (int i = 0; i < 50; ++i)
    array[i] = number; // where "number" is the number you want to set all the elements to

or as a shortcut, use std::fill

int array[50];

std::fill(array, array + 50, number);

If the number you want to set all the elements to is 0 , you can do this shortcut:

int array[50] = { };

Or if you're talking about std::vector , there is a constructor that takes the initial size of the vector and what to set each element to:

vector<int> v(50, n); // where "n" is the number to set all the elements to.

Answer 4

for(int i=0;i<sizeofarray;i++)
array[i]=valuetoassign

using method


void func_init_array(int arg[], int length) {
  for (int n=0; n<length; n++)
   arg[n]=notoassign
}