如何将数组的每个成员乘以javascript中的标量？

Question

例如，如何在不迭代数组的情况下实现以下目标？

var a = [1, 2, 3] * 5;  // a should equal [5, 10, 15]

Answer 1

Array.map() is available to IE users as of IE9, so if you don't care about compatibility at all you can use this:

var a = [1, 2, 3].map(function(x) { return x * 5; });

For JavaScript 1.8, this is as short as you can go:

var a = [1, 2, 3].map(function(x) x * 5);

If you need maximal browser compatibility, you'll have to put up with a loop.

Either way you'll be iterating over the array; Array.map() just makes it less obvious you're doing so.

Answer 2

In ECMAScript 6, you can use arrow functions :

var a = [1, 2, 3];
var b = a.map(x => x * 5); // <-------

console.log(b);   // [5, 10, 15]

---

Arrow functions are syntactic sugar for an inline function with lexical this binding:

// ES6
let array2 = array1.map(x => x * 5);

// ES5
var array2 = array1.map((function (x) { return x * 5; }).bind(this));

Therefore, if you need to support Internet Explorer or other old browsers (Edge understands ES6) you can use babeljs or TypeScript in your project to cross-compile your code to ES5 syntax.

Answer 3

for(var i=0; i<a.length; i++) {
    a[i] *= 5;
}

Answer 4

Ecmascript 2016 (ES7) defines SIMD mathematics which allow to do multiplications like the one you desire faster and easier. However, as of today there is very little browser support for SIMD (only Firefox nightly builds support this) [ 1 ], [ 2 ]. This is how it will look like:

var a = SIMD.Float32x4(1, 2, 3);
var b = SIMD.Float32x4(5, 5, 5);
SIMD.Float32x4.mul(a, b);  // Float32x4[5, 10, 15]

Until there will be widespread support for SIMD you'd have to resort to using map

var a = [1, 2, 3].map(function(x) { return x * 5; });

which is nicely supported by all modern browsers [ 3 ].

Answer 5

As stated in Docs :

The map() method creates a new array with the results of calling a provided function on every element in the calling array.

In my opinion, .map() is more suitable if someone wants to create a new array based on input values from the current array.

However, if someone wants to modify the array in place, .forEach() seems a better choice.

In ES6 we may use:

• Array.prototype.forEach()
• Arrow functions

Following code will modify a given array arr in place (without creating a new one):

arr.forEach((value, index) => {arr[index] *= 5});

Demo:

 var arr = [1, 2, 3]; var scalar = 5; arr.forEach((value, index) => { arr[index] *= scalar; }); console.log(arr);

Answer 6

You can use .map but you also have to create a new variable to throw the new values in:

var a = [1,2,3];

var b = a.map(function(x){
    return x * 5;
});

alert(b);

Answer 7

var a, i, ii, term;

a = [1,2,3];
term = 5;

for (i=0, ii=a.length; i<ii; i++) {
  a[i] = a[i] * term;
}

Answer 8

You can try this:

function scalarMultiply(arr, multiplier) {
   for (var i = 0; i < arr.length; i++)
   {
      arr[i] *= multiplier;
   }
   return arr;
}

USAGE

var a = scalarMultiply([1, 2, 3], 5);

Answer 9

使用 Lodash 的 map 函数，这将返回原始数组a乘以常量5 ：

_.map(a, function multiply(x) { return x * 5; });

Answer 10

I think it's not possible without iteration.

with iteration, here are the methods:

let a=[1,2,3,4] 

then,

method 1:

a=a.map(e=>{return e*5})

method 2:

a.forEach((e,i)=>a[i]=5*e)