带有回调函数的string.replace中的正则表达式

Question

 function helpLinkConvert(str, p1, offset, s)  {  
      return "<a href=\"look.php?word="
               +encodeURIComponent(p1)+"\">"+p1+"</a>";
     }

var message = "(look: this) is a (look: stackoverflow) question";
message = message .replace(/\(look: (.{1,80})\)/, helpLinkConvert);

This is what I want to do,

Before:

(look: this) is a (look: stackoverflow) question.

After:

this is a stackoverflow question

---

When there is only one matched string, it's working but in other cases It's not working properly,

How can I do that? Thanks.

Answer 1

You need to add the global g modifier , and a non-greedy match so the regular expression finds all matches:

/\\(look: (.{1,80}?)\\)/g

In your code:

function helpLinkConvert(str, p1, offset, s) {  
    return "<a href=\"look.php?word="+encodeURIComponent(p1)+"\">"+p1+"</a>";
}

var message = "(look: this) is a (look: stackoverflow) question";
message = message.replace(/\(look: (.{1,80}?)\)/g, helpLinkConvert);

Outputs:

"<a href="look.php?word=this">this</a> is a <a href="look.php?word=stackoverflow">stackoverflow</a> question"

Answer 2

Use the g flag:

message .replace(/\(look: (.{1,80})\)/g, helpLinkConvert);

The g (stands for "global") will match against all occurrences of the pattern on this string, instead of just the first one.